Question

the weight of an object on the earths surface is 300N. when it is lifted to 3 times the height, its weight will become

Answer 1

Answer:

The weight of the object when it is lifted to 3 times the height is 33.$\overline 3$ N

Explanation:

The given parameters are;

The weight of the object on Earth, W = 300 N

The initial position of the object = On the surface of the Earth

Therefore;

The distance with which the weight is measured = The radius of the Earth, R

By Newton's Law of Gravitation, we have;

$W = G \times \dfrac{M \times m}{R^2}$

Where;

W = 200 N

G = The universal gravitational constant

M = The mass of the Earth

m = The mass of the object

When the height of the object = 3 × R, the weight of the object, W₂, is given as follows;

$W_2 = G \times \dfrac{M \times m}{(3 \times R)^2} = \dfrac{1}{9} \times G \times \dfrac{M \times m}{ R^2} = \dfrac{1}{9} \times W = \dfrac{1}{9} \times 300 N = 33.\overline 3 \ N$

Therefore, the weight of the object at 3 times the height, W₂ = 33.$\overline 3$ N