Answer:
Calculate the mass of 6.022 × 1023 molecule of Calcium carbonate (CaCO3).
Solution —
Molar mass (Molecular mass in gram) of CaCO3 = 40+12+3×16 = 100 g
No. of moles of CaCO3
= No. of molecules/Avogadro constant
= 6.022 × 1023/ 6.022 × 1023
= 1 mole
Mass of CaCO3
= No. of moles × molar mass
= 1 × 100 g = 100 g.
Answer:
The value of the total internal energy produced during this process is 450 J.
Explanation:
The expression for the work done in terms of force and displacement is as follows;
W=Fs
Here, W is the work done, F is applied force and s is the displacement.
Calculate the work done.
Put F= 25 N and s= 30 m in the above expression.
W=(25)(30)
W= 750 J
The expression for the work done in terms of the change in the kinetic energy from work energy theorem is as follows;
Here, is the change in the kinetic energy.
Total internal energy= work done - kinetic energy
Put work done= 750 J and kinetic energy= 300 J.
Total internal energy=750 - 300
= 450 J
The remaining energy will get transformed into internal energy.
Therefore, the value of the total internal energy produced is 450 J.
<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>
Explanation:
Given:
= 10 rev/s =
= 15 rev/s =
= 60 rev =
a) the angular acceleration is given by
b)
c)
d)
Answer:
46.98 kg m/s
Explanation:
P = mv
P = 5.8*8.1 = 46.98 kg m/s