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dem82 [27]
3 years ago
12

An 8.00 g bullet is fired into a 250 g block that is initially at rest at the edge of a table of 1.00 m height. The bullet remai

ns in the block, and after the impact the block lands d=2.1 m from the bottom of the table. Determine the initial speed of the bullet.
Physics
1 answer:
Vsevolod [243]3 years ago
5 0
<span>79.75m/s  .................................</span>
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Answer:

4.30 x 10⁵ N/C

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a = length of the square of side = 0.50 m

r = distance of the center from each corner = \frac{a}{sqrt(2)} = \frac{0.50}{sqrt(2)} = 0.354 m

Magnitude of net electric field at the center is given as

E = \frac{2kq}{r^{2}} \\E = \frac{2(8.99\times10^{9})(3\times10^{-6})}{(0.354)^{2}} \\E = 4.30\times10^{5} NC^{-1}

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