The equilibrium reaction, causes the water dissociation constant, Kw, is 1.01 × 10-14<span> at 25 °C. That is because every H</span>+<span> (H</span>3O+) ion these forms accompanied by the formation of an OH-<span> ion, are the concentrations of these ions and in pure water the same thing can be calculated from </span>Kw<span>.
HOPED THIS HELP OUT ;)
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Explanation:
BIOMEDICAL IMPORTANCE
In addition to serving as precursors of nucleic acids, purine and pyrimidine nucleotides participate in metabolic functions as diverse as energy metabolism, protein synthesis, regulation of enzyme activity, and signal transduction.
I would say 2 because co2 goes out and o goes in
Answer: The volume of 0.235 M
needed to titrate 40.0 mL of 0.0500 M
is 8.51 ml
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is 
We are given:

Putting values in above equation, we get:

Thus volume of 0.235 M
needed to titrate 40.0 mL of 0.0500 M
is 8.51 ml
32.) 55.6 mL HCl
33.) 0. 128 M