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Anna71 [15]
3 years ago
10

You are walking in a clear-cut section of forest a few days after a heavy rainstorm. A nearby stream is very muddy and has many

dead fish. What might have happened?
Chemistry
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

the storm knocked down trees creating a dam blocking the path for water to move

Explanation:

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liberstina [14]
It Emeterio near the North Pole of the worlddddddd
3 0
3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
3 years ago
What volume of a 0.200 M HCI solution is needed to neutralize 25.0 L of a 0.250 M NaOH solution? Follow these steps
Zolol [24]

Answer: A little bit confused can you explain what I have to do

Explanation:

3 0
2 years ago
The $15 million land deal that took place as a result of the Treaty of Guadalupe Hidalgo was known as
adoni [48]

Answer:

Revolution of Guadlupe

Explanation:

6 0
3 years ago
A student determines that a 9.8 g mixture of MgCl₂ (s) and NaNO3(s) contains 0.050 mol of
Damm [24]

mass MgCl₂ = mol x MM MgCl₂ = 0.05 x 95.211 g/mol = 4.76 g

mass Cl in MgCl₂ :

= (2 x AM Cl)/MM MgCl₂ x mass MgCl₂

= (2 x 35.5 g/mol)/95.211 g/mol x 4.76

= 3.55 g

% mass Cl in the mixture :

= (mass Cl / mass mixture) x 100%

=  3.55 / 9.8 x 100%

= 36.22%

6 0
2 years ago
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