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Anna71 [15]
3 years ago
10

You are walking in a clear-cut section of forest a few days after a heavy rainstorm. A nearby stream is very muddy and has many

dead fish. What might have happened?
Chemistry
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

the storm knocked down trees creating a dam blocking the path for water to move

Explanation:

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1. What is the electron configuration of bromine atom?
Ganezh [65]

Answer:

[Ar] 3d¹⁰ 4s² 4p⁵

Explanation:

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7 0
3 years ago
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What is the major use of carbon monoxide
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Carbon monoxide is a very important industrial compound. In the form of producer gas or water gas.

hope ths help and if you want more information go to this website: science.jrank.org

8 0
2 years ago
Hich type of formula represents the simplest whole-number ratio of atoms of the elements in a compound?
klasskru [66]
I believe it is "empirical formula"
8 0
3 years ago
WILL GIVE BRAINLIEST
Alex777 [14]

For the first one, you have to find one that has both a metal and a nonmetal in it, plus potassium. Bonds between nonmetals are called covalent because they share electrons and a bond between a metal and a nonmetal is an ionic bond because they exchange electrons.

Potassium chloride is KCl. Only an ionic bond.

Potassium hydride is KH. Only an ionic bond.

Potassium nitrate is KNO3. There we go, that has a covalent bond between the nitrogen and oxygen, and an ionic bond between potassium and the nitrogen and oxygen.

For the second one, potassium chloride is the answer because the other three also have covalent bonds. Chloride is the only one that isn't a compound.

3 0
3 years ago
In the laboratory you are asked to make a 0.175 m barium iodide solution using 13.9 grams of barium iodide. How much water shoul
BARSIC [14]

<u>Answer:</u> The mass of water that should be added in 203.07 grams

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m = molality of barium iodide solution = 0.175 m

m_{solute} = Given mass of solute (barium iodide) = 13.9 g

M_{solute} = Molar mass of solute (barium iodide) = 391.14 g/mol

W_{solvent} = Mass of solvent (water) = ? g

Putting values in above equation, we get:

0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g

Hence, the mass of water that should be added in 203.07 grams

4 0
3 years ago
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