Answer:
The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.
Explanation:
Distance refers to the length between any two points in space, while displacement refers to the distance from a start position to an end position regardless of the path.
In other words, distance refers to how much space an object travels during its movement; is the quantity moved. It is also said to be the sum of the distances traveled. The distance traveled by a mobile is the length of its trajectory and it is a scalar quantity. In this case, the distance is calculated as:
1850 m + 1200 m= 3,050 m
Displacement refers to the distance and direction of the final position from the initial position of an object. The displacement effected is a vector quantity. The vector representing the displacement has its origin in the initial position, its end in the final position, and its module is the distance in a straight line between the initial and final positions. That is, when expressing the displacement it is done in terms of the magnitude with its respective unit of measurement and the direction because the displacement is a vector type quantity. Mathematically, the displacement (Δd) is calculated as:
Δd= df - di
where df is the final position and di is the initial position of the object.
In this case, the displacement is calculated as:
1850 m - 1200 m= 650 m
Since the distance to the north is greater, the direction of travel will be to the north.
<u><em>The distance it has traveled is 3,050 m and the magnitude of its displacement is 650 m north.</em></u>
Answer:
The magnetic field at a distance of 19.8 cm from the wire is 1.591 mT
Explanation:
Given;
first magnetic field at first distance, B₁ = 2.50 mT
first distance, r₁ = 12.6 cm = 0.126 m
Second magnetic field at Second distance, B₂ = ?
Second distance, r₂ = ?
Magnetic field for a straight wire is given as;

Where:
μ is permeability
B is magnetic field
I is current flowing in the wire
r distance to the wire

Therefore, the magnetic field at a distance of 19.8 cm from the wire is 1.591 mT
The particles that carry charge through wires in a circuit are mobile electrons. The electric field direction within a circuit is by definition the direction that positive test charges are pushed. Thus, these negatively charged electrons move in the direction opposite the electric field.
Explanation:
It is given that,
Voltage of the battery, V = 12 V
Current, I = 100 ampere-hours
Energy stored is given by the product of power and time taken. So,

P is the power, 

P = 1200 watts
This power can be used for 1 hour or 3600 seconds
Energy, 
E = 4320000 J
So, the energy stored in this battery is 4320000 J. Hence, this is the required solution.
Answer:
74.86°C
Explanation:
P₂ = Vapour pressure of water at sea level = 760 mmHg
P₁ = Pressure at base camp = 296 mmHg
T₂ = Temperature of water = 373 K
ΔH°vap for H2O = 40.7 kJ/mol = 40700 J/mol
R = Gas constant = 8.314 J/mol K
From Claussius Clapeyron equation

T₁ = 347.996 K = 74.86°C
∴Water will boil at 74.86°C