rank | 1st | 2nd |TOTAL
------|-----+-------|----------
a | 6 + 9 | =15
b | 7 + 3 | =16
c | 9 + 7 | =23
d | 6 + 7 | =22
e | 8 + 1 | =?
If you add the 1st in line a (6) and you add it to the 1st in line b (7) + the 2nd in line b (3) you get 16. Repeat the same logic/pattern to all c,d..
This is the pattern to all this puzzle;
So the before last term is : 9+6+7 = 22
and the last term : 6+8+1 = 15
Answer:
what are the following??
Step-by-step explanation:
Answer:
no ( 9,22) is not a solution to the system of inequalities but 22os to long to fit in the space
Step-by-step explanation:
i hope this is helpful.
A cosine is just a sine shifted to the left by π/2. A cosine of 4x is shifted to the left by only π/8 because of the factor 4. Sketch them.
The region we're looking for is this sausage-shaped part between the cos and the sin.
The x intercepts are at π/8 for the cosine and π/4 for the sine. The midpoint between them is at (π/8 + π/4)/2 = 3/16π.
The region is point symmetric around the x axis, so the y coordinate of the centroid is 0.
So the centroid is at (3/16π, 0)
9514 1404 393
Answer:
- area: 114 square units
- perimeter: 44 units
Step-by-step explanation:
The figure is a trapezoid with bases 12 and 7, and a height of 12. The area formula is ...
A = (1/2)(b1 +b2)h
A = (1/2)(12 +7)(12) = 114 . . . square units area
__
The length of side AB can be found using the distance formula:
d = √((x2 -x1)^2 +(y2 -y1)^2)
d = √((6 -(-6))^2 +(1 -6)^2) = √(144 +25) = 13
The sum of the side lengths is then ...
13 +7 +12 +12 = 44 . . . units perimeter
