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IrinaVladis [17]

3 years ago

14

During a football game, the running back changes direction from running 4.5 m/s [N] to 4.5 m/s [S] over 8 s. What is the acceler

ation of the running back during that time?

1 answer:

Nimfa-mama [501]3 years ago

8 0

Explanation:

Take north to be positive and south to be negative.

a = (v − v₀) / t

a = (-4.5 m/s − 4.5 m/s) / 8 s

a = -1.125 m/s²

The acceleration is 1.125 m/s² south.

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If the western component of the wind is half of the south, what is the angle of the wind with the south?

den301095 [7]

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

$\tan(x) = \frac{opp}{adj}$

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

$\tan(x) = \frac{ - \frac{a}{2} }{ - a}$

$\tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2}$

Now we take the arctan or inverse tan of 1/2.

$\tan {}^{ - 1} ( \frac{1}{2} ) = 26.57$

3 0

2 years ago

Read 2 more answers

A student climbs to the top of the gym and drops a baseball to the ground below. A physics student standing nearby has a motion

sladkih [1.3K]

Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground ( $t$ ), measured in seconds, which is determined by the following kinematic formula:

$t = \frac{v-v_{o}}{g}$ (1)

Where:

$v_{o}$ , $v$ - Initial and final speeds of the baseball, measured in meters per second.

$g$ - Gravitational acceleration, measured in meters per square second.

If we know that $v_{o} = 0\,\frac{m}{s}$ , $v = 17\,\frac{m}{s}$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the time spent by the baseball is:

$t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s} }{9.807\,\frac{m}{s^{2}} }$

$t = 1.733\,s$

The baseball was falling during 1.733 seconds.

6 0

3 years ago

The ____ of emitted light depends directly on the energy between the two orbits and this determines the color of the light

Anna007 [38]

The <u>frequency</u> of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.

<h3>What is light?</h3>

Light can be defined as a form of electromagnetic waves that does not require any medium for its propagation. This ultimately implies that, light is a form of wave that is generally referred to as a visual signal because it can be seen with the eyes.

According to the model of light wave, the <u>frequency</u> of emitted light is directly proportional to the energy between the two orbits and this determines the color of the light.

<em>In conlcusion, the </em><u><em>frequency</em></u><em> of emitted </em><em>light</em><em> is highly dependent on the </em><em>energy</em><em> between the two (2) </em><em>orbits</em><em>.</em>

Read more on energy here: brainly.com/question/1242059

7 0

3 years ago

Does the size of the magnetic field change with the size of the magnet?

mestny [16]

Answer:

Not all of the time, it can also depend on the strength of the magnet.

Explanation:

say you have a small very strong magnet, that might work just as well as a large but week magnet.

4 0

3 years ago

Suppose a certain battery has an internal emf of 9.00 V but the potential difference across its terminals is only 80.0 % of that

Rudiy27

Answer:

$1140.48\times 10^{-6}J$

Explanation:

We have given that the battery has an internal emf of 9 volt

So E = 9 volt

Capacitance $C=44\mu F=44\times 10^{-6}F$

It is given that on the terminal voltage is only 80% of potential difference

So V = 0.8×9 = 7.2 volt

We know that energy stored in the capacitor is given by

$E=\frac{1}{2}CV^2=\frac{1}{2}\times 44\times 10^{-6}\times 7.2^2=1140.48\times 10^{-6}J$

8 0

3 years ago