Answer:
10 feet.
Explanation:
Conductors are considered outside the building when they installed. The requirement of NEC is above 10 feet for the clearance after the final grade for service conductors and cables where they are connected with the building, above the sidewalks and the to other areas which are accessible to the pedestrians.
Heavy crate sits at rest on the floor of a warehouse. you push on the crate with a force of 400 N, and it doesn't budge. The magnitude of the friction force on the crate in Newton is 400N
This is due to Friction force, which is defined as the resisting force that acts on a body when it is at rest (Static friction) or when it is in motion (Kinetic friction).
When a force is applied on a stationary body, the force of static friction starts to act on the body which prevents any relative motion between the object and surface. The magnitude of friction increases up to μsN, where μs is the coefficient of static friction. As the crate didn't budge, it means the amount of force applied was less than μsN. Hence the force applied was canceled by an equal and opposite amount of frictional force which was equal to 400N.
Learn more about frictional force here
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Answer:
6
Explanation:
We are given that
Slid width,a=0.110 mm=
Wavelength,
m
We have to find the number of diffraction maxima are contained in a region of the Fraunhofer single-slit pattern.
Using the formula
Hence, 6 diffraction maxima are contained in a region of the Fraunhofer single-slit pattern
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
Answer:
Answer:
480cm or 0.48m
Explanation:
Given parameter:
Speed of the train = 8cm/s
time of travel = 1minute
Unknown:
Distance traveled = ?
Solution:
Speed is the rate of change of distance with time. This suggests that mathematically;
Speed =
Distance covered = speed x time
Now to solve for the distance;
Convert the time to seconds;
60seconds = 1 minute
Distance covered = 8cm/s x 60s = 480cm
Distance covered is 480cm or 0.48m
