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stepladder [879]
4 years ago
8

what do you predict will happen when a crystal of potassium nitrate is added to the saturated solution as it cooled? what might

happen if no crystal were present?
Chemistry
1 answer:
UkoKoshka [18]4 years ago
3 0
If you add a potassium nitrate and saturated solution you will make a super-saturated solution of potassium nitrate. But what to expect with this process of adding these 2. It is that the result of this solution made/forms bigger crystals that have pointed ends. If there is no appearance of the crystal it shows that the solution is not yet cooled. 
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Hello, I would really appreciate it if you guys can answer the question below, it is for marks and I do not know the answer for
Taya2010 [7]

Answer:

Two human needs are food and water. We need food to survive so we dont starve to death. And water is most important because without water after around five days, you die. Heat technology could be fire. We use fire to distill salt water. Distilling salt water boils the bacteria and so it would be safe to drink. We also use fire to cook the food we have gotten or hunted so we dont get infected with deadly bacteria and viruses.

Explanation:

Hope this helps. Have a nice day!

3 0
3 years ago
I need help please thanks
harina [27]

The answer is A because when an atom has more electrons in its outer shell, It becomes more reactive

7 0
3 years ago
On platooooo
slavikrds [6]

Answer:

Your answer is B. Energy cannot be destroyed

Explanation:

The total amount of energy remains constant in an isolated system. It states that energy can neither be created nor destroyed, but it can change from one form to another.

7 0
3 years ago
Read 2 more answers
The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
Vinil7 [7]

Answer:

Here's what I get  

Explanation:

You want to dilute the original solution by a factor of 25 in two steps, so you could dilute it by a factor of 5 in the first step, then dilute the new solution by another factor of 5.

A. First dilution

Use a 10 mL pipet to transfer 10 mL of the original solution to a 50 mL volumetric flask. Make up to the mark with distilled water. Shake well to mix.

Use the dilution formula to calculate the new concentration.

\begin{array}{rcl}c_{1}V_{1} & = & c_{2}V_{2}\\0.01985 \times 10.00 & = & c_{2} \times 50.00\\0.1985 & = & 50.00 c_{2}\\\\c_{2}& = & \dfrac{0.1985}{50.00}\\\\& = & \text{0.003 970 mol/L}\\\end{array}

B. Second dilution

Repeat Step 1, using the 0.003 970 mol·L⁻¹ solution.

\begin{array}{rcl}c_{2}V_{2} & = & c_{3}V_{3}\\0.003970 \times 10.00 & = & c_{3} \times 50.00\\0.03970 & = & 50.00 c_{3}\\\\c_{3}& = & \dfrac{0.03970}{50.00}\\\\& = & \textbf{0.000 7940 mol/L}\\\end{array}\\\text{The concentration of the final solution is $\boxed{\textbf{0.000 7940 mol/L}}$}

3. Check:

Compare the final concentration with the original

\begin{array}{rcl}\dfrac{ c_{3}}{ c_{1}} & = & \dfrac{0.0007940}{0.01985}\\& = & \mathbf{\dfrac{1}{25.00}}\\\end{array}\\\text{The concentration of the final solution is } \boxed{\mathbf{\dfrac{1}{25}}} \text{ that of the original solution}

7 0
3 years ago
Calculate the molality of a solution that is prepared by mixing 25.5 ml of ch3oh (d = 0.792 g/ml and 387 ml of ch3ch2ch2oh (d =
Zanzabum
The solvent is <span>ch3ch2ch2oh with a volume of 387 mL which is equivalent to
387 mL (0.811 g/mL) (1 kg /1000 kg) = 0.3139 kg
The moles of the alchol is
25.5 mL (0.792 g/mL) (1 mol/32 g) = 0.631 mol
The molality is
0.631 mol / 0.3139 kg = 2.01 mol/kg</span>
8 0
3 years ago
Read 2 more answers
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