1.25 g x 22.4 l / 1 mol = 28 g/mol
Answer:
One can determine the specific heat of the metal through using the clarimeter, water, thermometer and using heat equations.
Explanation:
You can learn about heat effects and calorimetery through a simple experiment by boiling water and heating up the metal in it. Then, pour it into your calorimeter and the heat will flow from the metal to the water. The two equlibria will meet: the metal will loose heat into its surroundings (the water) and teh water will absorb the heat. The heat flow for the water is the same as it is for the metal, the only difference being is the negative sign indicating the loss of the heat of the metal.
In terms of theromdynamics, we can deteremine the heat flow for the metal becasue it would be equal to the mangnitued but opposite in direction. Thus, we can say that the specific heat of water qH2O = -qmetal.
Tips
- write cue cards on respiratory system
- get someone to test you on your notes (friend,Mum,sister,brother ect)
- copy down diagrams of the system
- get someone to test you on Digram
- play online interactive games to test your knowledge on the respiratory system
- go through your textbook write a checklist things you know things you need to improve on.
- watch YouTube clips on the respiratory system
