Insects breathe by using a system called tracheae. where are these tubes located on an insect
2 answers:
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1) First of all, let's find the resistance of the wire by using Ohm's law:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
by using the following relationship:
Where A is the cross-sectional area of the wire and L its length.
We already have its length
, while we need to calculate the area A starting from the radius:
And now we can find the resistivity:
where V is the potential difference applied on the wire, I the current and R the resistance. For the resistor in the problem we have:
2) Now that we have the value of the resistance, we can find the resistivity of the wire
Where A is the cross-sectional area of the wire and L its length.
We already have its length
And now we can find the resistivity:
Answer:
a) 9.00 m b) 6.00 m/s c) 12.00 m/s
Explanation:
a) If the acceleration is constant, and we know that the displacement during the first second was 3.00 m, as the boulder (assumed that we can treat it as a point mass) started from rest, we can say the following:
Δx = = 3.00 m
As t = 1 s, replacing in the expression above, and solving for a, we have:
= 6.00 m/s²
In order to know how far it travels during the second second, we need to know the value of the speed after the first second, as it is the initial velocity when the second second begins:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
The total displacement, during the second second, will be as follows:
Δx = v₀*t + = 6.00m/s*1s +
⇒ Δx = 9.00 m
b) At the end of the first second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*1s = 6.00 m/s
c) At the end of the second second, the final speed can be obtained as follows:
vf = v₀ + a*t ⇒ vf = 0 + 6 m/s²*2s = 12.00 m/s