Draw the Lewis structure for ammonia, NH3. Include lone pairs. In the Lewis structure:_______.
1 answer:
Answer:
4) All of the above.
Explanation:
Hello,
In this case, considering the attached picture wherein the Lewis dot structure is drawn, we realize that the nitrogen has a lone par of electrons, whereas the other three valence electrons are bonded with the three hydrogen atoms in order to obey the octet rule and form three bonding pairs for nitrogen and one bonding pair per hydrogen. Therefore, answer is 4) All of the above.
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Answer:
1. Butyraldehyde; 2. but-3-en-1-ol
Explanation:
1. Peak ≥ 160 ppm
The formula C₄H₈O shows that the Index of Hydrogen Deficiency = 1.
It could be caused by either a ring or a double bond.
A peak at ≥ 160 ppm strongly indicates a C=O group, so the rest of the molecule can contain no rings or double bonds.
There are no other heteroatoms, so the compound most be an aldehyde or a ketone.
One compound that meets these criteria is butyraldehyde, CH₃CH₂CH₂CH=O (see Fig. 1.)
2. No rings; all peaks < 160 ppm
If all peaks are < 160 ppm, there can no C=O group.
There is no ring, so there must be a C=C double bond.
There is no other unsaturation, so the O atom must be present as an alcohol or an ether.
One compound that meets these criteria is but-3-en-1-ol, CH₂=CHCH₂CH₂OH (see Fig. 2).
