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pychu [463]
2 years ago
11

Step 2: measure the area of the top of the syringe

Chemistry
1 answer:
Elena L [17]2 years ago
6 0

I am unsure if this is correct, but this might be the whole section:

  • The top of the syringe is a circle. You need to compute its area for use in later computations of pressure values. Start by using a ruler to measure the diameter. Estimate to the nearest 0.01 cm. <em>Answer: </em><em>3.60 </em><em>cm</em>
  • Divide by two to find the radius. Maintain significant figures. <em>Answer: </em><em>1.80 </em><em>cm</em>
  • Substitute the radius into the formula A = πr² to find the area of the top of the syringe. Maintain significant figures. <em>Answer: </em><em>10.2 </em><em>cm²</em>
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Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x?
monitta
The product of prime polynomials is equivalent to 36x3 – 15x2 – 6x is letter B which is 3x(3x – 2)(4x 1). Below is the solution. 

3x(3x - 2) (4x + 1)
= 9x2 - 6x (4x + 1)
= 36x3 + 9x2 + -  24x2 - 6x
= 36x3 - 15x2 - 6x
       
3 0
2 years ago
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Calculate the volume which 1.00 mole of a gas occupies at 1 atm and 298K?
elena-14-01-66 [18.8K]

Answer:

25.45 Liters

Explanation:

Using Ideal Gas Law PV = nRT => V = nRT/P

V = (1mole)(0.08206Latm/molK)(298K)/(1atm) = 25.45 Liters

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2 years ago
Describe how stirring, surface area and temperature affect the rate of dissolving.
denis23 [38]

Answer:

friction

Explanation:

since it has a high tempature the friction increases like blowing air in a furnace

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3 years ago
If 42 grams of carbon and 52 grams of oxygen are used, how many grams of CO2 will be produced (Hint: find the
zavuch27 [327]

Answer:

71.5g

Explanation:

The reaction equation is given as:

               C  +  O₂  →  CO₂

Mass of C = 42g

Mass of O₂  = 52g

Unknown:

Mass of CO₂ produced  = ?

Solution

Now to solve this problem, we have to find limiting reactant which is the one given in short supply in this reaction.

 The extent of the reaction is controlled by this reactant.

Find the number of moles of the given species;

 Number of moles  = \frac{mass}{molar mass}

      Number of moles of C  = \frac{42}{12}   = 3.5mol

     Number of moles of O₂   = \frac{52}{32}   = 1.63mol

Now;

   From the balanced reaction equation;

           1 mole of C reacted with 1 mole of O₂

We see that C is in excess and O₂ is the limiting reactant.

            1 mole of O₂ will produce 1 mole of CO₂

 So;      1.63mole of O₂ will produce 1.63 mole of CO₂

Mass of CO₂ = number of moles x molar mass

       Molar mass of CO₂ = 44g/mol

Mass of CO₂ = 1.63 x 44 = 71.5g

8 0
2 years ago
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