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ikadub [295]
4 years ago
14

. Determine the horizontal and vertical components of reaction at the hinge A and the horizontal reaction at the smooth surface

B caused by the water pressure. The plate has a width of 4 ft. Start your solution by presenting the appropriate FBD. rhow = 1.94 slug/ft3 .

Physics
1 answer:
yan [13]4 years ago
6 0

Answer:

Please find attached file for complete answer solution and explanation of same question.

Explanation:

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A 500 Kg load is lifted through a vertical height of 10m in 25s by a crane. Calculate the power of the crane
denis23 [38]

Answer:

1962 W

Explanation:

P = W/t

P = F d cos theta / t

P = (500 kg) (9.81 m/s^2) (10 m) (cos 180) / 25 s  <-- the displacement and the force act in opposite directions (but it doesn't matter because direction doesn't matter in this case)

P = 1962 W

8 0
2 years ago
You watch distant Sally Homemaker driving nails into a front porch at a regular rate of 1 stroke per second. You hear the sound
san4es73 [151]

Answer:

d = 343 m

Explanation:

As we know that the speed of sound in air is given as

v = 343 m/s

now the rate of strike is 1 stroke per second

so distance is given as

d = v t

now we will have

t = 1 s

d = 343 \times 1

so the distance is given as

d = 343 m

5 0
3 years ago
Consider massive gliders that slide friction-free along a horizontal air track. Glider A has a mass of 1 kg, a speed of 1 m/s, a
mamaluj [8]

Answer:

0.167m/s

Explanation:

According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.

Given momentum = Maas × velocity.

Momentum of glider A = 1kg×1m/s

Momentum of glider = 1kgm/s

Momentum of glider B = 5kg × 0m/s

The initial velocity of glider B is zero since it is at rest.

Momentum of glider B = 0kgm/s

Momentum of the bodies after collision = (mA+mB)v where;

mA and mB are the masses of the gliders

v is their common velocity after collision.

Momentum = (1+5)v

Momentum after collision = 6v

According to the law of conservation of momentum;

1kgm/s + 0kgm/s = 6v

1 =6v

V =1/6m/s

Their speed after collision will be 0.167m/s

6 0
3 years ago
During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f
Lana71 [14]

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

v= speed of star

R= radius of star

i= initial

f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

8 0
4 years ago
When the moon is between the earth and the sun what moon phase will this be
Aleksandr [31]

Answer:  The new moon phase occurs when the Moon is directly between the Earth and Sun. A solar eclipse can only happen at new moon. A waxing crescent moon is when the Moon looks like crescent and the crescent increases ("waxes") in size from one day to the next. This phase is usually only seen in the west.

3 0
3 years ago
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