Complete Question
The complete question is shown on the first uploaded image
Answer:
The maximum emf is
The emf induced at t = 1.00 s is
The maximum rate of change of magnetic flux is
Explanation:
From the question we are told that
The number of turns is N = 44 turns
The length of the coil is
The width of the coil is
The magnetic field is
The angular speed is
Generally the induced emf is mathematically represented as
Where is the maximum induced emf and this is mathematically represented as
Where is the magnetic flux
N is the number of turns
A is the area of the coil which is mathematically evaluated as
Substituting values
substituting values into the equation for maximum induced emf
given that the time t = 1.0sec
substituting values into the equation for induced emf
The maximum induced emf can also be represented mathematically as
Where is the magnetic flux and is the maximum rate at which magnetic flux changes the value of the maximum rate of change of magnetic flux is
Answer:
Explanation:
The 3 kg box will have a downward force of its weight (Mg) and a balancing upward force of the normal force from the table. It will have a horizontal force T pointed towards the hanging mass side from the connecting cable.
The 2 kg hanging box will have a downward force of its weight (mg) and an upward force T from the connecting cable
Answer: option d: The nucleus of Atom Q is more stable than the nucleus of Atom P.
Explanation:
Atom P is radioactive and disintegrates, it emits beta particles (high speed electrons or positrons) because it is not stable. On disintegration, it forms a stable Atom Q which is non-radioactive and thus it does not disintegrates further.
Thus, the correct option is only d. The nucleus of Atom Q is more stable than the nucleus of Atom P.
Let h = the thickness of ice, m.
Because the ice covers an area of 0.65 m², the volume of ice is
V = 0.65h m³
The density of ice is 917 kg/m³, therefore the mass of ice is
m = (917 kg/m³)*(0.65h m³) = 596.05h kg
The latent heat of fusion of ice is 3.35 x 10⁵ J/kg, therefore the heat required to melt the ice is
Q₁ = (596.05h kg)*(3.35 x 10⁵ J/kg) = 2h x 10⁸ J
The electric heater supplies heat at 12 V, 23 A for 4.3 minutes to melt the ice.
Therefore the heat provided is
Q₂ = (12 V)*(23 A)*(4.3*60 s) = 71208 J
Because Q₁ = Q₂, obtain
2h x 10⁸ = 71208
h = 356 x 10⁻⁶ m = 356 x 10⁻³ mm = 0.356 mm
Answer: 0.356 mm
Explanation:
freshwater is defined as having a low salt concentration usually less than 1%