Inertia<span> and Mass. </span>Newton's first law of motion<span> states that "An object at rest stays at rest and an object in </span>motion<span> stays in </span>motion<span> with the same speed and in the same</span>direction<span> unless acted upon by an unbalanced force." Objects tend to "keep on doing what they're doing."</span>
Answer:
1.
2.
3.
Explanation:
The velocity vector is
1. The position vector can be found by integrating the velocity vector.
At t = 0, the bird is at the origin, so the integration constants can be determined.
Therefore, C1 and C2 are equal to zero.
2. The acceleration vector is the derivative of the velocity vector with respect to time.
3. We will first find the time when the x-component of the position vector is equal to zero.
We will plug in this value into the y-component of the position vector.
Complete Question:
What force (in N) must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2100 kg car (a large car) resting on the slave cylinder
? The master cylinder has a 2.00-cm diameter and the slave has a 24.0-cm diameter
Answer:
Explanation:
Given
--- mass
--- diameter of the large cylinder
--- diameter of the slave cylinder
To do this, we apply Archimedes' principle of buoyancy which implies that:
Where
<em /><em />
<em /><em />
<em /><em />
<em /><em />
<em />
Calculating the area of the master cylinder.
Calculating the area of the slave cylinder.
Substitute these values in:
Multiply both sides by
The force exerted on the slave cylinder (F2) is calculated as:
Substitute 20580 for F2 in
<em>Hence, the force exerted on the master cylinder is approximately 142.92N</em>
The kinetic energy at the top of the rock trajectory is 43.57 Joules
The kinetic energy formula and the procedure we will use is:
K.E. = 1/2 m (v*cosθ)²
Where:
- v = speed
- m = mass
- θ = angle
- Joules = Kg m²*s²
Information of the problem:
- v = 32 m/s
- m = 0.145 Kg
- θ = 40°
Applying kinetic energy formula we get:
K.E. = 1/2 m (v*cosθ)²
K.E. = 1/2 * 0.145 kg (32 m/s*cos40°)²
K.E. = 1/2 * 0.145 kg *(24.513 m/s)²
K.E. = 1/2 * 0.145 kg *600.91 m²/s²
K.E. = 87.132 kg m²/s² / 2
K.E. = 43.57 Joules
<h3>What is kinetic energy?</h3>
It is the energy possessed by a body due to its relative motion. It is usually expressed in Joules (J).
Learn more about kinetic energy at brainly.com/question/114210
#SPJ4