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Scorpion4ik [409]
3 years ago
8

The primary gases of the atmosphere are _____. nitrogen and carbon dioxide nitrogen, oxygen, and argon nitrogen and oxygen nitro

gen, oxygen, and carbon dioxide
Physics
2 answers:
Paladinen [302]3 years ago
6 0
<span>The primary gases of the atmosphere are _____:
</span>
nitrogen, oxygen, and carbondioxide
inna [77]3 years ago
3 0

Answer:

nitrogen and oxygen

Explanation:

You might be interested in
A dragster and driver together have mass 931.9 kg . The dragster, starting from rest, attains a speed of 25.7 m/s in 0.57 s. Fin
Mama L [17]

Answer:

45.09 m/s^2

Explanation:

from the question we were given the following parameters

mass = 931.9 kg

initial velocity (V1) = 0 m/s ( since it started from rest )

final velocity (V2) = 25.7 m/s

time (t) = 0.57 s

The average acceleration is given by:

a = ( V2 - V1 ) / t

therefore

a = (25.7 - 0) / 0.57 = 45.09 m/s^2

7 0
3 years ago
What electric force would a stationary 3.8 C charge experience if it were far away from any other charges
MAVERICK [17]

Answer:

The electric force will be  0 N

Explanation:

From the question we are told that

   The magnitude of the charge is  q_1 = 3.8 \ C

   

Generally from Coulombs law the electric force  between two charges is mathematically represented as

         F = \frac{ k  *  q_1 q_2 }{r^2}

Here r is the distance of separation between that two charges.

  Now from the question we are told that the charge is far away from any other charge hence we can say that the distance between the charge and any other charge is  r = \infty

So

       F = \frac{ k  *  3.8  * q_2 }{\infty^2}

=>    F =0 \ N

Hence the electric force will be  0 N

3 0
2 years ago
What erases the impact craters on earth and is responsible for most of the landforms that we see?
frez [133]
The big bang theory I think
6 0
3 years ago
A coyote can locate a sound source with good accuracy by comparing the arrival times of a sound wave at its two ears. Suppose a
jeka94

Answer:

a)  t_l - t_r = 12.54 us

b)  (t_l - t_r) / T = 0.0157  

Explanation:

Given:

- Frequency of source f = 1250 Hz

- Distance from source to right ear d_r = 2.6 m

- Distance from source to left ear d_l = ?

- Separation between ears s = 0.15 m

Find:

a. What is the difference in the arrival time of the sound at the left ear and the right ear?

b. What is the ratio of this time difference to the period of the sound wave?

Solution:

- Apply Pythagoras theorem to calculate the distance d_l from source to left ear:

                                      d_l = sqrt ( 2.6^2 + 0.15^2)

                                      d_l = sqrt ( 6.7825 )

                                      d_l = 2.6043 m

- The time deference can be calculated from a simple distance - speed formula:

                                      t_l - t_r = (1 / v) * ( d_l - d_r)

Where, v = 343 m/s speed of sound in air:

                                      t_l - t_r = (1 / 343) * ( 2.6043 - 2.6)  

                                      t_l - t_r = ( 0.0043 / 343 )

                                      t_l - t_r = 12.54 us

- Now we compute the Time period of the sound wave:

                                      T = 1 / f

                                      T = 1 / 1250 = 8*10^-4 s

- The ratio of differential time to Time period T is:

                                      (t_l - t_r) / T = 12.54 * 10^-6 / 8*10^-4

                                      (t_l - t_r) / T = 0.0157  

3 0
3 years ago
Find the weight of an object with mass 80 kg on the moon ( g = 1.6 m/s^2)
SpyIntel [72]

Answer:

80kg = 133 Newtons I'm pretty sure this is right.

5 0
2 years ago
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