1. An oxide of chromium is found to have the following % composition: 68.4% Cr
1 answer:
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Answer:
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene
The name of given molecule is 3-Methylpent-2-ene.
Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.
Molecule sketched was named as,
1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,
2-Pentene or Pent-2-ene
2) The position of substituent was specified before the parent name, Hence,
3-Methyl-2-Pentene or 3-Methylpent-2-ene
Answer:
2.4506 x
Explanation:
move decimal point to the right 1 time : 24506
24506 becomes 2.4506
count how many numbers after decimal point and that becomes b
b = 4
Answer:
new volume is 1215mL
Explanation:
using Charles law , the volume of a fixed mass of gas is directly proportional to its temperature provide that pressure is kept constant.
V1=900mL ,
convert the temperatures from Celsius to kelvin temperature.
T1 =27°C =27+273 =300K
T2 =132°C = 132+273=405K
V2= 1215mL