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777dan777 [17]
4 years ago
13

Elevator mass 750kg tension on cable 8950n what is the net force action on the elevator

Physics
1 answer:
Hunter-Best [27]4 years ago
8 0
The answer to this question i think would be 8950. Do you have any answer choices.
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Is stored energy<br><br> kinetic energy <br> potential energy <br> both
Murrr4er [49]
Potential energy is stored energy while kinetic is energy in motion. So the answer is potential energy.
6 0
4 years ago
Which of these is NOT a type of lever?<br> A. rake<br> B. ramp<br> C. crowbar<br> D. scissors
ICE Princess25 [194]
Rake bc it does not use anything no lever or anything
3 0
3 years ago
Read 2 more answers
A 75 A resistor in a circuit has a current flowing through it of 2.0 A. What is
Reptile [31]

Answer:

The power dissipated by the resistor can be calculated as P = I^{2} R .

Explanation:

  • Joules heating law states that any conductor passed with the electric current produces heating effect which is the electric power loss.
  • The given circuit has, R = 75 ohm resistor (the unit is wrong i question because resistor's unit is ohm not Ampere).
  • Current flowing through the circuit is I = 2.0 A.
  • By using joules heating theory, P = I^{2} R,

                  or,   P = 2^{2} * 75

                  or,   P= 4*75

                 or,  P= 300 W.

  • So the power dissipated by the resistor in the circuit is 300 W.
7 0
3 years ago
Light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. The sheet has parallel faces and the glass h
xxMikexx [17]

Answer:

30.81°

Explanation:

θ₁ = angle of incidence = 50°

θ₂ = Angle of refraction

n₂ = Refractive index of glass = 1.5

n₁ = Refractive index of air = 1.0003

From Snell's Law

Using Snell's law as:

n_1\times {sin\theta_1}={n_2}\times{sin\theta_2}

1.0003\times {sin50}={1.50}\times{sin\theta_2}

Angle of refraction= sin⁻¹ 0.5122 = 30.81°.

3 0
4 years ago
an athlete runs 300 m up a hill at a steady speed of 3.0 m/s. She then immediately runs the same distance at 6.0 m/s . What is h
mina [271]

Answer:

4.0 m/s

Explanation:

In the first part of the run, the athlete runs a distance of

d_1 = 300 m

at a speed of

v_1 = 3.0 m/s

So, the time he/she takes is

t_1 = \frac{d_1}{v_1}=\frac{300}{3.0}=100 s

In the second part of the run, the athlete covers an additional distance of

d_2 = 300 m

with a speed

v_2 = 6.0 m/s

So, the time taken in this second part is

t_2 = \frac{d_2}{v_2}=\frac{300}{6.0}=50 s

So, the total distance covered is

d = 300 m + 300 m = 600 m

And the total time taken

t = 100 s + 50 s = 150 s

Therefore, the average speed for the entire trip is

v=\frac{d}{t}=\frac{600}{150}=4.0 m/s

4 0
4 years ago
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