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nignag [31]
4 years ago
9

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a _____ to the la

unch points.
Physics
2 answers:
yarga [219]4 years ago
4 0
Force against

Hope that helped :)


NemiM [27]4 years ago
4 0

Answer

Force

Explanation:

To understand this problem it is necessary to understand Newtons third law

Newtons third law

According to Newtons third law, "For every action there is equal and opposite reaction".

In all types of jumping Newton's third law is applied

Every jumper while jumping applies a  force with their legs to the launch point  due to which a reactive force is  generated and this reactive force push the jumper away from the launch point.

More the force applied by the jumper more will be reactive force which push the jumper away.

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Answer:

The maximum kinetic energy is 100 j.    

Explanation:

<h3>The kinetic energy = (potential energy) + (kinetic energy) and the potential energy of 0 J implying its kinetic energy is 100 J, which is its maximum. </h3>

4 0
3 years ago
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This picture represents the electric field diagram between two particles with static charges. Do the two particles have the same
dexar [7]

Answers:

No, They will attract each other, B, and neither direction

Explanation:

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3 years ago
Estimate how far apart the rays of deepest red and deepest violet light are as they exit the bottom surface. assume nred = 1.57
Harlamova29_29 [7]
We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
n_1sin(\theta_1)=n_2sin(\theta_2)
Where \theta_2 differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
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\theta_{2red}=Asin(\frac{sin(30)}{1.57})\approx 18.5705
\theta_{2violet}=Asin(\frac{sin(30)}{1.60})\approx 18.21
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d_{violet}=h.tan(\theta_{2violet})\approx 0.0132m
For red we have:
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\Delta x=d_{red}-d_{violet}\approx2.8\times10^{-4}m


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