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Harrizon [31]
3 years ago
7

What is 1/2 / 1/4. Please help am getting two answers.idk the correct one.​

Physics
1 answer:
Alla [95]3 years ago
5 0

Answer:

2

hope this helps :)

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Which statement best describes the process that produced the ending populations of moths
zzz [600]
C. Light color became an adaptation in the surviving moths? Not fully sure.
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4 years ago
Read 2 more answers
A 100 kg boat is floating in water. half of the boat is submerged under water. what is the weight of the boat?
Alex17521 [72]
W=MG
w is weight 
m is mass
g is gravity 
W=(100 kg)(9.8 m/s)
W= 980 N
hope this helps
7 0
3 years ago
A car has a mass of 1300 kg and a velocity of 15 m/s. The car crashes into a wall and stops in two seconds. What is the stopping
Musya8 [376]

Answer:

B

Explanation:

Newton's second law:

F = ma

The acceleration is Δv/Δt, so:

F = m Δv/Δt

Given m = 1300 kg, Δv = 15 m/s, and Δt = 2 s:

F = (1300 kg) (15 m/s) / (2 s)

F = 9750 N

Answer B.

3 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 2000 j of heat, starting from 19 ∘c?
RSB [31]
The boiling point of ethanol is at 78.37°C. So, the energy must include sensible heat to raise 19°C to the boiling point and latent heat to change liquid to gas. The equation would be

Energy = Sensible heat + Latent heat
Energy = mCpΔT + mΔH

For ethanol, 
Cp = 46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ J/kmol·K
ΔH = 38,560 J/mol

Integrate the Cp expression to determine CpΔT:

CpΔT = ∫₂₉₂³⁵²(46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ )dT
The upper limit is (78.37+273) = 352 K, while the lower limit is (19 + 273) = 292.
CpΔT = 2384857192 J/kmol·K

2,000 J = m(2384857192 J/kmol)(1 kmol/1000 mol) + m(38,560 J/mol)
m = 8.253×10⁻⁴ moles of ethanol
Since the molar mass of ethanol is 46.07 g/mol,
Mass = (8.253×10⁻⁴ mol)(46.07 g/mol)
Mass = 0.038 g ethanol
8 0
4 years ago
A frictionless piston–cylinder device contains 7 kg of nitrogen at 100 kPa and 250 K. Nitrogen is now compressed slowly accordin
lora16 [44]

Answer: -1038.8 kJ

Explanation:

From the question, we can see that PV^n = constant. And as such, we can deduce that it is a polytropic process. Thus, we can use the polytropic work equation to calculate the needed work input.

from the question we were given

Mass of nitrogen, m = 7kg

initial temperature, T1 = 250k

Final temperature, T2 = 450k

Polytropic index, n = 1.4

Specific gas constant, R = 0.2968kJ/kgK

W = [p2 * v2 - p1 * v1] / 1 - n

W = [m * R * T2 - T1] / 1 - n

W = 7*0.2968*(450 - 250)] / 1 - 1.4

W = [7*0.2968*200] / -0.4

W = 415.52 / -0.4

W = -1038.8 kJ

5 0
3 years ago
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