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arlik [135]
3 years ago
7

In the following reaction, H3PO4 (aq) + H2O (l) ⇄ H2PO4– (aq) + H3O+ (aq) what happens when more H2PO4– (aq) is added to the sol

ution?
Chemistry
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

The concentration of H₃PO₄ will increase.

Explanation:

H₃PO₄(aq) + H₂O(l) ⇄ H₂PO₄⁻(aq) + H₃O⁺(aq)

According to Le Châtelier's Principle, when we apply a stress to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

If we add more H₂PO₄⁻, the position of equilibrium will move to the left to get rid of the added H₂PO₄⁻.

The concentration of H₃PO₄ will increase.

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When the temperature of the air is 25°C, the velocity of a sound wave traveling through the air is approximately
Vitek1552 [10]

Answer ; The correct answer is : 346 m/s .

Sound is a type of longitudinal wave , which is produced when a matter compress or refracts .

Speed of sounds depends on factors like medium , density , temperature etc .

Effect of Temperature on speed of sounds :

When the temperature increases , molecules gains energy and they starts vibrating and with higher temperature vibration becomes fast . So the waves of sounds can travel faster due to faster vibrations . Hence , speed of sounds is directly proportional to the temperature or speed of sounds increases with increase in temperature .

The speed of sounds at 0⁰C is 331 \frac{m}{s}

The relation between speed of sound and temperature is given as :

V = 331 \frac{m}{s}  + ( 0.6 \frac{m}{s- ^0C} * T  )

Given : Temperature = 25 ⁰ C

Plugging values in formula =>

V = 331 \frac{m}{s} + (0.6 \frac{m}{s-^0C}  * 25^0C)

V = 331 \frac{m}{s} + 15 \frac{m}{s}

V =  346 \frac{m}{s}

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How do the cells in your body get energy?
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3 years ago
What is the difference in mesomeric and electromeric effect​
Leya [2.2K]

Cause their are both have difference s

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When you turn on the heat in the car, heat is being transferred by (1 point)
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A. Radiation 

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5 0
3 years ago
How many liters of phosphine are produced when 34 L of hydrogen reacts with an excess of phosphorus under STP?
Keith_Richards [23]

Answer:

22.67 L of PH₃

Explanation:

The balanced equation is:

P_4 (s) + 6H_2(g) \to 4PH_3(g)

From the equation:

34 L \times \dfrac{1 \ mol \ of H_2 }{22.4 \ L \ H_2} \times \dfrac{4 \ mol \ of \ PH_3}{6 \ mol \ H_2} \times \dfrac{22.4 \ L \ PH_3}{1 \ mol \ PH_3}

= 22.67 L of PH₃

5 0
3 years ago
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