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arlik [135]
3 years ago
7

In the following reaction, H3PO4 (aq) + H2O (l) ⇄ H2PO4– (aq) + H3O+ (aq) what happens when more H2PO4– (aq) is added to the sol

ution?
Chemistry
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

The concentration of H₃PO₄ will increase.

Explanation:

H₃PO₄(aq) + H₂O(l) ⇄ H₂PO₄⁻(aq) + H₃O⁺(aq)

According to Le Châtelier's Principle, when we apply a stress to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

If we add more H₂PO₄⁻, the position of equilibrium will move to the left to get rid of the added H₂PO₄⁻.

The concentration of H₃PO₄ will increase.

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Write this number in standard notation.<br> 1.986 x 10negative exponent 6 or 1.986 x 10^6
Brums [2.3K]

Answer:

0.000001986

Explanation:

We have the number 1.986*10^{-6}. Standard notation would basically be this number without the 10^{-6} part.

To get rid of this part, we need to move the decimal point 6 places to the left (we go left because it's negative 6, indicating division).

So, when we move the decimal point 6 places to the left, the resulting number is: 0.000001986, with 5 zeros after the decimal point before a nonzero number.

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7 0
3 years ago
A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number
Cloud [144]

Answer : The distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

Explanation :

As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

                    = 1440 minutes

Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

                                                                                     = 3168 cm

                                                                                     = 3.2\times 10^3cm

Now we have to convert 'cm' into 'pm'.

Conversion used : 1cm=10^{10}pm

As, 1cm=10^{10}pm

So,  3.2\times 10^3cm=\frac{3.2\times 10^3cm}{1cm}\times 10^{10}pm=3.2\times 10^{13}pm

Therefore, the distance covered by slow snail in 24 hours is 3.2\times 10^{13}pm

4 0
4 years ago
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