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Anna11 [10]
4 years ago
15

Why is it important to balance a chemical equation

Chemistry
2 answers:
igomit [66]4 years ago
7 0
Because a balanced equation gives you the molar ratios of all the reactants and products for the reaction.
avanturin [10]4 years ago
6 0
It is important to balance a chemical equation <span>because there must be an equal number of atoms on both sides of the </span>equation<span> to follow the Law of the Conservation of Mass.</span>
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Classify the items based on whether they are or are not matter.
Phantasy [73]

Answer:

Matter:

toothpaste

gasoline

bacteria

cell

Not matter:

happiness

sound

Explanation:

Matter is something that has mass and volume. Happiness is just a feeling, it doesn't exist in 3d world. Sound is a wave or just the movement of matter (particles of matter). Others have masses and volumes.

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3 years ago
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3 years ago
An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
sleet_krkn [62]

Answer:

Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+

Explanation:

The total number of proton present in an atom is known as the atomic number of that atom.From that point of view the atomic number of iron ion is 26.

  The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton

 According to the given question iron ion contain 3 more protons than electrons as a result the iron ion will contain 3 unit positive charge.

5 0
3 years ago
which one of the following groups are decomposers a. algae b. protist c. fungi d. green plants e. photosynthetic bacteria
alukav5142 [94]

Answer:c

Explanation:

7 0
3 years ago
2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2
nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with H_2 to form CH_4 and H_2O. balanced reaction is:

CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

No. of moles of CO = 0.800 mol

No. of moles of H_2 = 2.40 mol

Volume = 8.00 L

Concentration = \frac{Moles}{Volume\ in\ L}

Concentration of CO = \frac{0.800}{8.00} = 0.100\ mol/L

Concentration of H_2 = \frac{2.40}{8.00} = 0.300\ mol/L

                 CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g)  +  H_2O(g)

Initial            0.100      0.300             0   0

equi.            0.100 -x    0.300 - 3x     x    x

It is given that,

at equilibrium H_2O (x) = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium H_2 = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium CH_4 = 0.0386 M

Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}

Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90

8 0
3 years ago
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