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3 years ago

Green light travels by what type of wave? (2 points) a Conductive b Electronic c Conducive d Electromagnetic 2

Physics

1 answer:

zhannawk [14.2K]3 years ago

8 0

Answer:

Electromagnetic

Explanation:

Electromagnetic waves are those waves that do not require any material medium for propagation. They arise from a vibration of electric and magnetic fields.

The electromagnetic spectrum is comprised of many waves. One of the waves in the spectrum is visible light.

Visible light is in turn composed of seven different wavelengths of which green light is one of them. Hence, green light travels by electromagetic wave.

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What physical quantity is a measure of the amount of inertia an object has?

allochka39001 [22]

3 0

3 years ago

In a photoelectric experiment it is found that a stopping potential of 1.00 V is needed to stop all the electrons when incident

kiruha [24]

Answer:

Planck’s constant is $6.9*10^{-34} Js$

work function of metal is $5.846*10^{-19}$

Explanation:

The maximum kinetic energy from electron from photoelectric effect is given by

$\K_{max}=eV_o$ where $V_o$ is applied voltage and e is charge on electron and substituting charge on electron by $1.6*10^{-19}$ and 1.00 V for $V_o$

$K_{max}=1.6*10^{-19}*1=1.6*10^{-19} J$

Considering that the wavelength, \lambda of light used is given as $278*10^{-9} m$

Energy of light is given by

$E=\frac {hc}{ \lambda}$ where $\lambda$ is the wavelength, h is Planck’s constant and c is speed of light. Taking c for $3*10^{8} m/s$

Substituting values of wavelength and speed of light we obtain

$E=\frac {h*3*10^{8}}{278*10^{-9}}=h1.07914*10^{15} J$

If work function is $\phi$ then

$E=\phi + k_{max}$ hence

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$ ------- Equation 1

Energy corresponding to wavelength of 207 nm is

$E=h\frac {3*10^{8} m/s}{207*10^{-9}}=h(1.45*10^{15}}) J$

Maximum kinetic energy of electrons when $V_o$ is 2.6 V becomes

$K_{max}=(1.6*10^{-19})*2.6V=4.16*10^{-19} J$

From $E=\phi + k_{max}$ and substituting $h(1.45*10^{15}}) J$ for E and $4.16*10^{-19} J$ for $K_{max}$ we have

$h(1.45*10^{15}}) J=\phi +4.16*10^{-19} J$ ------ Equation 2

Equation 2 minus equation 1 gives

$h3.71*10^{14}=2.56*10^{-19}$

$h=\frac {2.56*10^{-19}}{3.71*10^{14}}\approx 6.9*10^{-34} Js$

Therefore, Planck’s constant is $6.9*10^{-34} Js$

Recalling equation 1 and substituting back the value of h as obtained

$h1.07914*10^{15} J=\phi +1.6*10^{-19} J$

$(6.9*10^{-34})*(1.07914*10^{15})=\phi +1.6*10^{-19} J$

$\ph=(6.9*10^{-34})*(1.07914*10^{15})-(1.6*10^{-19})=5.846*10^{-19}$

Therefore, work function of metal is $5.846*10^{-19}$

5 0

4 years ago

constant force F=5i+5j−1kF=5i+5j−1k is applied to an object that is moving along a straight line from the point (−5,−3,−4)(−5,−3

meriva

Answer:

W = 71J

Explanation:

Given force F = (5i+5j−1k)N

d = Δr

r1 = (−5,−3,−4)m

r2 = (2,5,0)m

Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))

Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m

W = F•d = (5i+5j−1k)•(7i+ 8j +4k)

W = 5×7 + 5×8 +-1×4 = 35 + 40 - 4

W = 71J

6 0

3 years ago

5. The value of a car decreases by 15% each

Kazeer [188]

Answer:

the car is worth $2,400

Explanation:

6000*15%=900

900*4=3600

6000-3600=2400

6 0

3 years ago

Your mother is sure that you were driving too fast because she knows (2 points)

Finger [1]

The answer is either answer B or answer C! Hope that helps

3 0

3 years ago