Answer:
Explanation:
A mass of 700 kg will exert a force of
700 x 9.8
= 6860 N.
Amount of compression x = 4 cm
= 4 x 10⁻² m
Force constant K = force of compression / compression
= 6860 / 4 x 10⁻²
= 1715 x 10² Nm⁻¹.
Let us take compression of r at any moment
Restoring force by spring
= k r
Force required to compress = kr
Let it is compressed by small length dr during which force will remain constant.
Work done
dW = Force x displacement
= -kr -dr
= kr dr
Work done to compress by length d
for it r ranges from 0 to -d
Integrating on both sides
W = 
= [ kr²/2]₀^-4
= 1/2 kX16X10⁻⁴
= .5 x 1715 x 10² x 16 x 10⁻⁴
= 137.20 J
Answer:
They both tend to develop during the spring (March-June), reach peak intensity during the late autumn or winter (November-February), and then weaken during the spring or early summer (March-June)
In that case, heat energy flows from the warmer object to the cooler one.
As heat flows from one to the other, the temperature of the warmer object
falls, and the temperature of the cooler object rises. When the temperatures
are equal, the flow of heat energy from one to the other stops.
Answer:
list of spring in order of increasing spring constant is given by,
W, Y, X, Z
Explanation:
Spring W:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 20 / 0.5
k = 40 N/m
Spring X:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 60 / 0.3
k = 200 N/m
Spring Y:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 40 / 0.4
k = 100 N/m
Spring Z:
Magnitude of Force applied on the spring is given by,
F = k x
Where, F = force applied
k = spring constant
x displacement
k = F/x
k = 50 / 0.1
k = 500 N/m
Thus, list of spring in order of increasing spring constant is given by,
W, Y, X, Z
