Objects fall at constant velocity

2 answers:

5 0

No they don't. Without air resistance, objects fall with constant
acceleration.

On Earth, the acceleration is 9.8 m/s² ... the speed of a falling object
at any time is 9.8 m/s faster than it was 1 second earlier.

ch4aika [34]2 years ago

5 0

False,
Object do not intend to fall at a constant velocity.

You might be interested in

Describe the agronomic significance of the upper and lower plastic limits, and of the plasticity index?

GarryVolchara [31]

Answer:It shows the size of the range of the moisture contents at which the soil remains plastic. In general, the plasticity index depends only on the amount of clay present. It indicates the fineness of the soil and its capacity to change shape without altering its volume.

4 0

3 years ago

bagirrra123 [75]

Explanation:

The reading on the scale is

W = m(g + a)

= (77 kg)(9.8 m/s^2 + 2 m/s^2)

= 908.6 N

7 0

2 years ago

The speed of a wave in a medium is effected by____,____, and____

lisov135 [29]

$\huge\mathfrak\green{answer}$

As per as my knowledge

The speed of a wave in a medium is affected by density, wavelength and temperature :)

(Good luck on your test and mark me brainliest if this helps)

7 0

2 years ago

2 ways in which the effects of friction can be minimised in the experiment

Vlad [161]

Answer:

Friction can be minimized by using lubricants like oil and grease and by using ball bearing between machine parts. A substance that is introduced between two surfaces in contact, to reduce friction, is called a lubricant. Fluid friction can be minimized by giving suitable shapes to the objects moving in the fluids.

Explanation:

hope it helps

7 0

2 years ago

If the Earth and distant stars were stationary (motionless) in space, what would we observe about the wavelength from these star

dangina [55]

1) In the first case, the correct answer is
A.Wavelengths measured would match the actual wavelengths emitted.
In fact, the stars are not moving relative to Earth, so there is no shift in the measured wavelength.

2) In this second case, the correct answer is
A.Wavelengths measured would be shorter than the actual wavelengths emitted.
in fact, since the stars in this case are moving towards the Earth, then apparent frequency of their emitted light will be larger than the actual frequency, because of the Doppler effect, according to the formula:
$f'= \frac{c}{c+v_s} f_0$
where f0 is the actual frequency, f' the apparent frequency, c the speed of light and vs the velocity of the source (the stars) relative to the obsever (Earth). Vs is negative when the source is moving towards the observer, so the apparent frequency f' is larger than the actual frequency f0. But the wavelength is inversely proportional to the frequency, so the apparent wavelength will be shorter than the actual wavelength.

6 0

2 years ago