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faust18 [17]
3 years ago
5

A 75-m-long train begins uniform acceleration from rest. the the train has a speed of 23 m/s when it passes a railway worker tan

ding 180 m from where the front of the train started what will be the speed of the last car as it passes the worker? front of moving. what will 75 m y23 m/s
Physics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

acceleration a = 1.04 m/s2

Explanation:

Assume the train has a speed of 23m/s when the last car passes the railway workers. Once this happens the last car would have traveled a total distance of the 180m distance between the railway worker standing 180 m from where the front of the train started plus the 75m distance from the first car to the last car:

s = 75 + 180 = 255 m

We can use the following equation of motion to find out the distance traveled by the car:

v^2 - v_0^2 = 2aswhere v = 23 m/s is the velocity of the car when it passes the worker, v_0 = 0m/s is the initial velocity of the car when it starts, a m/s2 is the acceleration, which we are looking for.

23^2 - 0^2 = 2*a*255

510a = 529

a = 529 / 510 = 1.04 m/s^2

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If your front lawn is 18.0 feet wide and 20.0 feet long, and each square foot of lawn accumulates 1050 new snowflakes every minu
Sedbober [7]

Answer:

47628 kg/hr

Explanation:

Total area = 18*20 =360 ft^(2)

no .of snowflakes per minute = 1050*360 =378000

mass of snowflakes per minute = 378000*2.1*10^(-3) =793.8 kg/min

mass accumulated per hour = 793.8kg/min * 60min/hr =47628 kg/hr

7 0
3 years ago
A horizontal spring is attached to the wall on one end and to a mass on the other end. The mass can slide freely on a frictionle
Radda [10]

Answer:

a) x=0  %T=0,   b) x= A %T=100%,   c) x=-A %T=50%

Explanation:

This is a simple harmonic movement exercise, which is explained by the expression

          x = A cos (wt + Ф)

where angular velocity is related to frequency and period

         w = 2π f = 2π / T

we can write the equation of the oscillation

         x = A cos θ

When seeing the two equations they are equivalent, so what happens with the angle will also happen with time

We are asked for the percentage of the period at three points: at the maximum elongation and at the point of x = 0, in general the distance is measured from the point of the spring without stretching

The period is defined as the time that the system takes to give a complete oscillation, that is, from x = 0 to x = A and return

a) for the unstretched spring point x = 0

In general, both distance and time are measured from this point, so the percentage of time is zero.

         % T = 0

b) for x = A

 let's find the angle

      cos tea = x / A = 1

therefore the angles tea = 2π rad

when the movement reaches the point of 2π radians it begins to repeat so the period is complete

            % T = 100%

c) the point of maximum compression x = -A

let's look for the angles

      cos tea = x / A = -1

therefore the angles tea = π rad

at this point the movement is halfway so it should take half the time

                % T = 50%

6 0
2 years ago
Answer the answers that you know.
sesenic [268]
1).  Sequence from the Sun:

       Inner planets:
                 Mercury
                 Venus
                 Earth
                 Mars

       Outer planets:
                 Jupiter
                 Saturn
                 Uranus
                 Neptune
            
2).  The farther a planet is from the sun, the longer it takes
to orbit the sun.  Mercury ... 88 days.  Earth ... 365 days.
                           Jupiter ... 12 years.    Neptune ... 165 years.

3).  Mercury & Venus ... no moons
      Earth - 1
      Mars - 2
     Jupiter -  more than 65

4).  Mercury ... cratered, no atmosphere
      Venus ... cratered, thick cloudy atmosphere
       Mars ... dry, cratered, slight atmosphere, like 1% or Earth's
      
       Jupiter, Saturn, Uranus, Neptune
                     We can't see any surface.  If any of them even
                     HAS a surface, it's thousands of miles under a
                     thick atmosphere of methane gas.

5).  Missing from the list

6).  Here's a list from the biggest planet to the smallest one.
The numbers in parentheses are the radius of the planet --
half of the diameter:

Jupiter (69,911 km / 43,441 miles) – 1,120% the size of Earth
Saturn (58,232 km / 36,184 miles) – 945% the size of Earth
Uranus (25,362 km / 15,759 miles) – 400% the size of Earth
Neptune (24,622 km / 15,299 miles) – 388% the size of Earth
Earth (6,371 km / 3,959 miles)
Venus (6,052 km / 3,761 miles) – 95% the size of Earth
Mars (3,390 km / 2,460 miles) – 53% the size of Earth
Mercury (2,440 km / 1,516 miles) – 38% the size of Earth

7). At least seven of the planets rotate in the same direction. 
There's something different about one of them ... it may be Uranus
but I'm not sure.  You'll have to look this up.

8).  Saturn has the famous rings, that you can almost see
with only binoculars.
Spacecraft sent to observe the outer planets have detected
very thin rings around Uranus and Neptune.

9).  Included in #6.

10).  I don't have complete info.  Generally, the closer the planet
is to the sun, the hotter it is.  But there are a few exceptions. 
I think Venus ... the second one from the sun, is actually hotter
than Mercury. 

11).  Just about every language has its own name for each planet.

12).  "Terrestrial" means "like Earth" ("Terra").
The terrestrial planets are the ones that have solid surfaces
and are made of rock.
Mercury, Venus, Earth, and Mars.

13).  "Jovian" means "like Jupiter".
Either no solid surface, or very small, inside a big deep gas ball. 
Jupiter, Saturn, Uranus, Neptune.


4 0
3 years ago
I need to show my work as well but on the computer so, please show work for how you got the answers. Thank you!
balandron [24]

Answer:

1) 1H_2 + 1Cl_2 => 2HCl

2) 2Al + 6HCl => 2AlCl_3 + 3H_2

3) 1Ca_2Br_2 + 2NaCO_3 => 2CaCO_3 + 2NaBr

4) 3NaOH + 1FeCl_3 => 3NaCl + 1Fe(OH)_3

Explanation:

4 0
2 years ago
You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In j
Feliz [49]

The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

E= \frac{1}{2} kx^2

where;

k is the spring constant

x is the compression/stretching of the string

In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

E=\frac{1}{2} (150) (0.3)^2

E=6.75J

Therefore. the elastic potential energy stored in the spring is 6.75J .

Learn more about potential energy here:

brainly.com/question/10770261

#SPJ4

6 0
1 year ago
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