Answer:
Horizontal component = 16.8 m/s
Vertical component = 46.0 m/s
Explanation:
If we denote the initial velocity by <em>v</em> and the angle above the horizontal by <em>θ</em>,
the horizontal component of this initial velocity is given by
The vertical component is given by
Answer:
Compression Test
Explanation:
The Specimen is undergoing a compression test. It is similar to tensile test with the difference that the force is compressive and applied along the direction of stress. Both Tensile and compression tests are performed on Universal Testing machine. Compression test is done to determine the product's reaction when it is compressed, squashed and crushed.
The original kinetic energy will be 0 J and the final kinetic energy will be 7500 J and the amount of work utilized will be similar to the final kinetic energy i.e., 7500 J.
<u>Explanation:</u>
As it is known that the kinetic energy is defined as the energy exhibited by the moving objects. So the kinetic energy is equal to the product of mass and square of the velocity attained by the car. Thus,
So the initial kinetic energy will be the energy exerted by the car at the initial state when the initial velocity is zero. Thus the initial kinetic energy will be zero.
The final kinetic energy is
= 7500 J
As the work done is the energy required to start the car from zero velocity to 5 m/s velocity.
Work done = Final Kinetic energy - Initial Kinetic energy
Thus the work utilized for moving the car is
Work done = 7500 J - 0 J = 7500 J
Thus, the initial kinetic energy of the car is zero, the final kinetic energy is 7500 J and the work utilized by the car is also 7500 J.
Answer:
So time taken by block to travel 0.5 m from rest will be 0.4853 sec
Explanation:
We have given mass of the block m = 6.7 kg
angle of inclination
Distance traveled s = 0.5 m
Initial velocity u = 0 m/sec
Acceleration of the block
From second equation of motion we know that
So
t = 0.4853 sec
So time taken by block to travel 0.5 m from rest will be 0.4853 sec