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3 years ago

How does inertia affect a person who is not wearing a seatbelt during a collision?

1 answer:

6 0

An object in motion will stay in motion, therefore the person will still be going the same speed as the car was going before the collision

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The question and options are in the photo

inessss [21]

Answer:

Option C

Explanation:

Metal conducts heat much better than wood does.

Since Azam's hand is hotter than room temperature, both the metal and the wood conduct heat away from it.

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3 years ago

What is Newton's law of motion

const2013 [10]

Explanation:

Newton’s first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force

2nd- is a quantitative description of the changes that a force can produce on the motion of a body.

3rd- states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.

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3 years ago

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EJ is taking his little sister, Ebony, on her first carousel ride. His mass is 75.0 kg and her mass is 10.0 kg. They ride the sa

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3 years ago

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A person takes a trip, driving with a constant speed of 89.5km/h, except for a 22.0−min rest stop. If the person's average speed

Elanso [62]

Answer:

stop using brainly and learn this bs in class

Explanation:

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4 years ago

Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the ce

Elena L [17]

Answer:

The value is $\lambda = 900 \ nm$

Explanation:

From the question we are told that

The width of the slit is $a = 0.15 \ mm = 0.00015 \ m$

The distance of the screen from the slit is D = 1.25 m

The width of the central maximum is $y = 0.75 \ cm = 0.0075 \ m$

Generally the width of the central maximum is mathematically represented as

$y = \frac{m * D * \lambda}{a}$

Here m is the order of the fringe and given that we are considering the central maximum, the order will be m = 1 because the with of the central maximum separate's the and first maxima

$\lambda = \frac{a y}{ m * D }$

=> $\lambda = \frac{ 0.000015 * 0.0075}{ 1 * 1.2 }$

=> $\lambda = 900 *10^{-9} \ m$

=> $\lambda = 900 \ nm$

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3 years ago