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Zina [86]
4 years ago
7

The function f(x) = 20(3)x represents the growth of a fish population every year in a local lake. Jesse wants to manipulate the

formula to an equivalent form that calculates every half-year, not every year. Which function is correct for Jesse's purposes? f(x) = 20(3)the x over 2 power f(x) = 20(3 to the one half power)2x f(x) = twenty halves(3)x f(x) = 40(2)x
Mathematics
2 answers:
lukranit [14]4 years ago
4 0
In the equation, 20 is the original number of fish so we do not change that value to compensate for growth every half year. We will have to change the rate of growth, i.e, 3 and bring 1/2 into its power,
f(x) = 20(3)^(x/2) is correct
GaryK [48]4 years ago
4 0
One year is represented by x. Therefore, half year would be represented by \frac{x}{2}. Now just substitute x with \frac{x}{2} in the formula y=20(3)^x.

y=20(3)^{ \frac{x}{2} }
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Owen is three years less than twice as old as his sister Sara if Owen is 13 how old is she
Likurg_2 [28]

Answer:

23

Step-by-step explanation:

If you are asking how old Sara is then....

the equation would be: S= (13×2)-3

(S is stands for Sara)

We are using 13 because Owen is 13 yrs old. We used 2 because it said twice. We are using three cause it said three less than. 13×2=26. 26-3  would be 23.

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3 years ago
In an arithmetic-sudoku, the values 1,2,3,4 appear exactly once in each row and each column. Which value belongs in the grey squ
Romashka [77]

Answer:

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Step-by-step explanation:

The number of rows and columns of the Sudoku is not stated; so, I will assume it is 5 by 5, since there is only one gray square left to be occupied.

If 1 - 4 appears in each row and 1 - 4 appears in each column (take for instance, the attached Sudoku image), then the value that should be entered in the gray square is 5.

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3 years ago
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Stolb23 [73]

n is even

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1 year ago
Suppose that the functions p and q are defined as follows.p(x) = -2x + 1q(x)=-x?Find the following.
MariettaO [177]

First let us find

(q\mathrm{}p)(x)\begin{gathered} q(p(x))=q(-2x+1) \\ =-(-2x+1)^2 \\ So\text{ } \\ (q\mathrm{}p)(5)=-(-2\times5+1)^2 \\ =-(9)^2 \\ =-81 \end{gathered}

Now let;s solve the second part

\begin{gathered} (p\mathrm{}q)(x)=p(q(x)) \\ =p(-x^2) \\ =-2(-x^2)+1 \\ =2x^2+1 \\ So\text{ (p.q)(5) will be } \\ (p\mathrm{}q)(5)=2(5)^2+1 \\ =51 \end{gathered}

6 0
1 year ago
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