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Gekata [30.6K]
3 years ago
8

Help me asap I rely need help u will be my fav​

Engineering
2 answers:
Nonamiya [84]3 years ago
5 0
The answer is C!!!!!!!!!
sladkih [1.3K]3 years ago
3 0

Answer:

The Answer is C!

Explanation:

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The majority of adults now own smartphones or tablets, and most of them say they use them in part to get the news. From 2004 to
noname [10]

Answer:

..... yes

Explanation:

5 0
3 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 106 GPa and an original cross-sectional diameter of 3.9
kiruha [24]

Answer:

L= 312.75 mm

Explanation:

given data

elastic modulus E = 106 GPa

cross-sectional diameter d = 3.9 mm

tensile load F = 1660 N

maximum allowable elongation ΔL = 0.41 mm

to find out

maximum length of the specimen before deformation

solution

we will apply here allowable elongation equation that is express as

ΔL =     \dfrac{FL}{AE}     ....................1

put here value and we get L

L   =    \dfrac{0.41\times 10^{-3}\times \dfrac{\pi}{4}\times (3.9\times 10^{-3})^2\times 106\times 10^9}{1660}

solve it we get

L = 0.312752 m

L= 312.75 mm

8 0
4 years ago
30POINTS
garri49 [273]
Concentrating solar power (CSP) plants use mirrors to concentrate the sun's energy to drive traditional steam turbines or engines that create electricity. The thermal energy concentrated in a CSP plant can be stored and used to produce electricity when it is needed, day or night. Today, roughly 1,815 megawatts (MWac) of CSP plants are in operation in the United States.

Parabolic Trough
Parabolic trough systems use curved mirrors to focus the sun’s energy onto a receiver tube that runs down the center of a trough. In the receiver tube, a high-temperature heat transfer fluid (such as a synthetic oil) absorbs the sun’s energy, reaching temperatures of 750°F or higher, and passes through a heat exchanger to heat water and produce steam. The steam drives a conventional steam turbine power system to generate electricity. A typical solar collector field contains hundreds of parallel rows of troughs connected as a series of loops, which are placed on a north-south axis so the troughs can track the sun from east to west. Individual collector modules are typically 15-20 feet tall and 300-450 feet long.

Compact Linear Fresnel Reflector
CLFR uses the principles of curved-mirror trough systems, but with long parallel rows of lower-cost flat mirrors. These modular reflectors focus the sun's energy onto elevated receivers, which consist of a system of tubes through which water flows. The concentrated sunlight boils the water, generating high-pressure steam for direct use in power generation and industrial steam applications.
3 0
3 years ago
Read 2 more answers
Three single-phase, 10 kVA, 460/120 V, 60 Hz transformers are connected to form a three-phase 460/208 V transformer bank. The eq
evablogger [386]

Answer:

A) attached below

B) I₁ = 18.1 A ,  I₂ = 69.39 A

C)  V( magnitude) = 454.5 ∠ 5.04° V ,  Voltage regulation = ≈  -1.2%

Explanation:

A) Schematic diagram attached below

attached below

<u>B) magnitude of primary and secondary winding currents </u>

I₂ ( secondary current ) = P / √3 * VL * cos∅ ---------- ( 1 )

VL = Line voltage = 208

cos∅  ( power factor ) = 0.8

P = 20 * 10^3 watts

insert values into equation 1

I₂ = 69.39 A

I₁ ( primary current ) = I₂V2 / V1

                               I₁ = ( 69.39 * 120 ) / 460  = 18.1 A

<u>C ) Calculate the Primary voltage magnitude and the Voltage regulation</u>

V(magnitude ) = Vp + ( I₁ ∠∅ ) Req                            ( 1 + j2 = 2.24 ∠63.43° )

                       = 460 + ( 18.1 * cos^-1 (0.8) ) ( 1 + j2 )

                       = 460 + 40.544 ∠ 100.3°

∴ V( magnitude) = 454.5 ∠ 5.04° V

<em>Voltage regulation </em>

= ((Vmag - V1) / V1 )) * 100

= (( 454.5 - 460 / 460 )) * 100

= -1.195 % ≈  -1.2%

8 0
3 years ago
A horizontal rigid bar ABC is pinned at end A and supported by two cables at points B and C. A vertical load P 5 10 kN acts at e
BARSIC [14]

Answer:

vertical load = 10 kN

Modulus of elasticity = 200GPa

Yield stress on the cable = 400 MPa

Safety factor = 2.0

Explanation:

Data

let L = \sqrt{(1.5)^{2} + (1.5)^{2} }

        = 3.35 m

substituting 1.5 m for h and 3 m for the tern (a + b)

\theta = tan⁻¹(\frac{1.5}{1.5})

  = 45⁰

substituting 1.5 for h and 3 m for (a+ b) yields:

\theta₂ = tan⁻¹ (\frac{1}{3})

   =25.56⁰

checking all the forces, they add up to zero. This means that the system is balanced and there is no resultant force.

6 0
3 years ago
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