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Gekata [30.6K]
3 years ago
8

Help me asap I rely need help u will be my fav​

Engineering
2 answers:
Nonamiya [84]3 years ago
5 0
The answer is C!!!!!!!!!
sladkih [1.3K]3 years ago
3 0

Answer:

The Answer is C!

Explanation:

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A 1020 CD steel shaft is to transmit 15 kW while rotating at 1750 rpm. Determine the minimum diameter for the shaft to provide a
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Answer:

diameter is 14 mm

Explanation:

given data

power = 15 kW

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factor of safety = 3

to find out

minimum diameter

solution

we will apply here power formula to find T that is

power = 2π×N×T / 60    .................1

put here value

15 ×10^{3} = 2π×1750×T / 60

so

T = 81.84 Nm

and

torsion = T / Z                        ..........2

here Z is section modulus i.e = πd³/ 16

so from equation 2

torsion = 81.84 / πd³/ 16

so torsion = 416.75 / / d³     .................3

so from shear stress theory

torsion = σy / factor of safety

so here σy = 530 for 1020 steel

so

torsion = σy / factor of safety

416.75 / d³ = 530 × 10^{6} / 3

so d = 0.0133 m

so diameter is 14 mm

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