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Talja [164]
3 years ago
15

Which type of fuel must be the most carefully contained and protected

Chemistry
1 answer:
12345 [234]3 years ago
5 0
What are the options for this question?
You might be interested in
How many grams of As2S3 are in 3.25 moles?
laiz [17]

Answer:

Explanation:

Molar mass of As2S3= {75(2) + 32(3)}

= 150 + 96 = 246g/mol

Amount = 3.25mole

And

Amount = mass/ molar mass

mass = amount × molar mass

Mass = 3.25 × 246

mass = 799.5g

6 0
4 years ago
4. If the earth were to heat up by 3 degrees, approximately how much would the sea level rise?
Ksju [112]

The sea level would rise by some 50 meters.

Explanation:

If the earth's temperature increases by 3 degrees the north and south pole would experience the ice melt at high speed.

The life will get difficult on the plains.

The extinction of some species will happen.

The sea level would rise by 50 meters. The increased sea level will cause depletion of habitat from plants and animals.

The floods will occur, land erosion, soil for agriculture land will get contaminated with the salt.

8 0
3 years ago
Which of the following represents a chemical change?
Snezhnost [94]
The answer is B.) Freezing of water
3 0
3 years ago
Please help. Thank you:)
bearhunter [10]
These are guesses because there is no word bank or anything

A. Water
B. Housing
C. Plants
D. Animals
E. Warmth
5 0
3 years ago
A sample of calcium phosphate was found to have a mass of 125.3 g. How many molecules were contained in the sample?
Viktor [21]

The answer for the following problem is mentioned below.

  • <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules.</em></u>

Explanation:

Given:

mass of calcium phosphate (Ca_{3}(PO_{4} )_{2} ) = 125.3 grams

We know;

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = (40×3) + 3 (31 +(4×16))

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} ) = 120 + 3(95)

molar mass of calcium phosphate  (Ca_{3}(PO_{4} )_{2} )  = 120 +285 = 405 grams

<em>We also know;</em>

No of molecules at STP conditions(N_{A}) = 6.023 × 10^23 molecules

To solve:

no of molecules present in the sample(N)

We know;

\frac{m}{M} =\frac{N} }{}N÷N_{A}

\frac{405}{125.3} =\frac{N}{6.023*10^23}

N =(405×6.023 × 10^23) ÷ 125.3

N = 19.3 × 10^23 molecules

<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are  19.3 × 10^23 molecules</em></u>

3 0
3 years ago
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