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zvonat [6]
3 years ago
8

The surface temperature of main-sequence stars increases as

Chemistry
1 answer:
sammy [17]3 years ago
5 0

the surface temp of main sequence star increase as diameter increases

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The numeral 4.21 has three significant fire two known figures d e figure numbers are always significant
Kamila [148]

The significant figures are always:

Different from zero except there are only zeros before the point.

You can round them to the previous significant.

In scientific notation, you have one figure point two more figures.

Examples:

You have 4.21

All different from zero and only two decimals.

Those are all significant figures.

if you have 000.231555

You will shorten this to two significant figures.

Before the point, you only have zeros, so you need to keep only one of them to say its less than one.

After the point, you have a lot of figures, but you need to round this to two.

Because you have a one before the three, you'll keep the three. If you have a five or bigger number, you round it.

In this case, you'll have 0.23 with two significant figures.

7 0
4 years ago
Help me plssssssssss
sweet-ann [11.9K]

Answer:

The answer for this selection is 4

Explanation:

7 0
3 years ago
The rate law for the reaction 2A + B →C is –rA= kACA2CBwithkA= 25 (L/mol)2sec. What arekBandkC?
givi [52]

Explanation:

The given reaction equation is as follows.

             2A + B \rightarrow C

So, rate constants for different reactants and products written as follows.

             \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

As per the reaction equation, the stoichiometric coefficients of reactants and products are as follows.

         A = -2

         B = -1

         C = 1

Therefore,

      \frac{-k_{A}}{\text{stoichiometric coefficient of A}} = \frac{-k_{B}}{\text{stoichiometric coefficient of B}} = \frac{k_{C}}{\text{stoichiometric coefficient of C}}

      \frac{-k_{A}}{-2} = \frac{-k_{B}}{-1} = \frac{k_{C}}{1}    

             \frac{-k_{A}}{-2} = k_{B} = k_{C}

Hence,          k_{B} = k_{C} = \frac{25}{2} (L/mol)^{2}

                                          = 12.5 (L/mol)^{2}

Thus, we can conclude that k_{B} and k_{C} are 12.5 (L/mol)^{2}.

5 0
4 years ago
Sulfur oxidation Choose one: A. contributes to global warming due to CO2 production. B. contributes to global warming due to met
iren2701 [21]

Answer:

C . causes environmental acidification due to production of sulfuric acid.

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El etanol combustiona con el oxigeno produciendo dióxido de carbono gaseoso y agua: En un proceso se hacen reaccionar 450.2 g de
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uh oh stinky uh oh stinky

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