The resulting pressure of the gas after decreasing the initial volume from 2 L to 1 L is 3 atm.
<h3>What is
Boyle's Law?</h3>
According to the Boyle's Law at constant temperature, pressure of the gas is inversely proportional to the volume of that gas.
For the given question we use the below equation is:
P₁V₁ = P₂V₂, where
P₁ = initial pressure of gas = 1.5 atm
V₁ = initial volume of gas = 2 L
P₂ = final pressure of gas = ?
V₂ = final volume of gas = 1 L
On putting all these values on the above equation, we get
P₂ = (1.5atm)(2L) / (1L) = 3 atm
Hence required pressure of the gas is 3 atm.
To know more about Boyle's Law, visit the below link:
brainly.com/question/469270
Amorphous is the answer. A glass is an amorphous solid.
Not sure if this was a true or false but ok great job it is true. :)
Answer:
When 0.250 moles of a gas is placed in a container at 25 °C, it exerts a pressure of 700 mm Hg.
Explanation:
Answer:
7.7439×10⁻³¹ m
Explanation:
The expression for Heisenberg uncertainty principle is:
Where m is the mass of the microscopic particle
h is the Planks constant
Δx is the uncertainty in the position
Δv is the uncertainty in the velocity
Given:
mass = 0.68 g = 0.68×10⁻³ kg
Δv = 0.1 m/s
Δx= ?
Applying the above formula as:
<u>Δx = 7.7439×10⁻³¹ m</u>
