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joja [24]
3 years ago
11

An AC generator with a variable frequency and an RMS voltage output of 120 Volts is connected in series to a 3.1 μF Capacitor an

d a 100 Ω resistor. The RMS voltage across the capacitor is measured to be 92 Volts. What is the RMS voltage across the resistor?
Physics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

The RMS voltage across the resistor = 28 V

Explanation:

Capacitor: A capacitor is an electrical device that has the ability to store electrical charges in an electrical circuit. It is expressed in Farad (F)

Resistor: A resistor is an electrical device that oppose the flow of electric current in a circuit. It is expressed in ohms (Ω)

RMS Voltage : RMS voltage  value of an alternating voltage is defined as that value of steady voltage which would dissipate heat at the same rate in a given resistance

Since the it is a series circuit, the total voltage is divided across the resistance and the capacitor.

Vt = V₁ + V₂...........................Equation 1

Where Vt = total Rms voltage = 120 V ,  V₁ = Rms voltage across the Capacitor = 92 V, V₂ = Rms voltage across the resistor.

Making V₂ the subject of the equation in equation 1 above,

V₂ = Vt - V₁  = 120 - 92

V₂ = 28 V.

The RMS voltage across the resistor = 28 V

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A racetrack has the shape of an inverted cone, as the drawing shows. On this surface the cars race in circles that are parallel
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Answer:

The value of d is 183.51 m.

Explanation:

Given that,

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Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

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Divided equation (I) by equation (II)

\tan\theta=\dfrac{v^2}{gr}

Put the value of g

\tan\theta=\dfrac{v^2}{g\times d\cos\theta}

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v^2=g\times d\sin\theta

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Put the value into the formula

d=\dfrac{(34.0)^2}{9.8\times\sin40}

d=183.51\ m

Hence, The value of d is 183.51 m.

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3 years ago
The reacting force that is equal to and opposite in the direction to the centripetal force and tends to fling air out of the cen
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Centrifugal force

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Two charges are located in the xx–yy plane. If q1=−4.10 nCq1=−4.10 nC and is located at (x=0.00 m,y=1.080 m)(x=0.00 m,y=1.080 m)
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Answer:

Explanation:

Due to first charge , electric field at origin will be oriented towards - ve of y axis.

magnitude

Ey = -8.99 x 10⁹ x 4.1 x 10⁻⁹ / 1.08² j

= - 31.6 j N/C

Due to second charge electric field at origin

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.2²+ .6²

= 8.99 x 10⁹ x 3.6  x 10⁻⁹ / 1.8

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It is making angle θ where

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= 26.55°

this field in vector form

= - 18 cos 26.55 i - 18 sin26.55 j

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= - 16.10 i - 8.04 j + ( - 31.6 j )

= -16.1 i - 39.64 j .

Ex = - 16.1 i

Ey = - 39.64 j .

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3 years ago
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