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andriy [413]
3 years ago
15

What is the current in the 60.0 resistor

Physics
2 answers:
Talja [164]3 years ago
8 0

Answer:

you must calculate it using the formula I=V/R

Artist 52 [7]3 years ago
7 0

Answer:

Option (c)

Explanation:

According to question,

R= 60 ohm

V=120 V

Current can be calculated as :

I=\frac{V}{R}

Where,

I  is current

V is voltage

R is resistance

I=\frac{120}{60} \\I=2 A

Current is flowing across 60 ohm will be 2.0 A

Therefore, option c is correct

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Why is the following situation impossible? The object of mass m = 4.00 kg in Figure P6.10 is attached to a vertical rod by two s
Crank
The situation is impossible mainly because we can't see Figure P6.10 .
It would undoubtedly be the same story on an another planet, until we
see the figure and understand what's going on.
4 0
3 years ago
An object is released from rest and falls a distance h during the first second of time. How far will it fall during the next sec
Viefleur [7K]

Answer:

E. 3h

Explanation:

We know that

u = 0 m/s.

velocity after t = 1s

v = u+gt = 0+9.81 x 1s= 9.81 m/s

distance covered in 1st sec

= =>> ut+0.5 x g x t²

=>>0 + 0.5x 9.81 x 1 = 4.90m

Let 4.90 be h

distance travelled in 2nd second will now be used

So velocity after t = 1s

=>>1 x t+ 0.5 x g x t²

=>9.81x 1 + 0.5 x 9.81 x 1 = 3 x 4.90

So since h= 4.90

Then the ans is 3x h = 3h

3 0
2 years ago
In attempting to pull a 1500-kg car out of a ditch, Arnold exerts a force of 300 N for three seconds, Bob exerts a force of 500
SpyIntel [72]

Answer:

Bob provided the greatest impulse.

Explanation:

Given:

Arnold exerts force = 300 N for 3 seconds

Bob exerts force = 500 N for 2 seconds

Cecil exerts force = 200 N for 4 seconds.

Find:

Highest impulse

Computation:

Impulse = Force × TIme

Arnold provides impulse = 300 N × 3 seconds = 900 N/s

Bob provides impulse = 500 N × 2 seconds = 1,000 N/s

Cecil provides impulse = 200 N × 4 seconds = 800 N/s

Therefore, Bob provided the greatest impulse.

8 0
3 years ago
How you do this resistor in circuit question?
lawyer [7]
If Resistors are in series= The equivalent is the sum.

E.g R1 and R2 in series,  R = R1 + R2.

If in Parallel, equivalent is Product/sum.

E.g If R1 and R2 in parallel,  R = (R1*R2)/(R1+R2)

1.)    60 is parallel with 40 and both are then in series with 20.

60//40   = (60*40)/(60+40) = 2400/100 = 24 

Now the 24 is in series with the 20 

R = 24 + 20 = 44 ohms.

2.)    80 is in series with 40 and both are then in parallel with 40.

Solving the series,  R = 80 + 40 =120.

Parallel:   120//40  =     (120*40)/(120+40) =  4800/160 = 30 
Equivalent Resistance = 30 ohms.

3.) 100 is in parallel with 100 and both are then in series with the parallel of 50 and 50.

The 1st parallel  =  (100*100)/(100+100) = 10000/200 = 50

The 2nd parallel  =  (50*50)/(50+50)  = 2500/100   = 25.

Solving the series  = 50 + 25 =75 ohms.

Cheers.
3 0
3 years ago
While accelerating at 5.22 m/s/s an object changes its velocity from 6.73 m/s to 29.88 m/s. Over what
yan [13]

Answer:

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s = (29.88² - 6.73²) / (2(5.22))

s = 81.1802203065...

s = 81.18 m

4 0
2 years ago
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