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Black_prince [1.1K]
3 years ago
9

Getting a haircut from a barber is an example of a service that can be purchased. Please select the best answer from the choices

provided. True or false?
Engineering
2 answers:
tia_tia [17]3 years ago
7 0

The correct answer is True

Explanation:

In the economy, a service refers to a benefit consumers obtain due to the skills, experience or abilities of the seller. A service differs from a product because the customer does not obtain a good. Examples of services include education, car-repair services or haircuts. Additionally, most services are purchased as you pay for them; although some such as education are covered by the government.

According to this, it is true, getting a haircut from a barber is an example of a service that can be purchased because the customer obtains a benefit (the haircut) rather than a good and needs to pay for it as this involves the skills and knowledge of the barber.

algol133 years ago
4 0

Answer:

True.

Explanation:

Getting a haircut is a service and you are purchasing this service of getting you hair styled and cut. So, I believe the answer would be true.

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Air enters a compressor operating at steady state with pressure of 90 kPa, at a temperature of 350 K, and a volumetric flow rate
natita [175]

Answer:

T_{out} = 457.921\,K

Explanation:

Before determining the exit temperature of air, it is required to find the specific enthalpy at outlet by using the First Law of Thermodynamics:

-\dot Q_{out} + \dot W_{un} + \dot m \cdot (h_{in}-h_{out})=0

h_{out} = \frac{\dot W_{in}}{\dot m}- q_{out} +h_{in}

An ideal gas observes the following mathematical model:

P\cdot V = n\cdot R_{u}\cdot T

Where:

P - Absolute pressure, in kilopascals.

V - Volume, in cubic meters.

n - Quantity of moles, in kilomole.

R_{u} - Ideal gas universal constant, in \frac{kPa\cdot m^{3}}{kmole\cdot K}.

T - Absolute temperature, in kelvin.

The previous equation is re-arranged in order to calculate specific volume at inlet:

P\cdot V = \frac{m}{M}\cdot R_{u}\cdot T

\nu = \frac{R_{u}\cdot T}{P\cdot M}

\nu_{in} = \frac{(8.314\,\frac{kPa\cdot m^{3}}{kmol\cdot K} )\cdot (350\,K)}{(90\,kPa)\cdot (28.97\,\frac{kg}{kmol} )}

\nu_{in} = 1.116\,\frac{m^{3}}{kg}

The mass flow is:

\dot m = \frac{\dot V}{\nu_{in}}

\dot m = \frac{0.6\,\frac{m^{3}}{s} }{1.116\,\frac{m^{3}}{kg} }

\dot m = 0.538\,\frac{kg}{s}

The specific enthalpy in ideal gases depends on temperature exclusively. Then:

h_{in} = 350.49\,\frac{kJ}{kg}

The specific enthalpy at outlet is:

h_{out} = \frac{75\,kW}{0.538\,\frac{kg}{s} }-30\,\frac{kJ}{kg} + 350.49\,\frac{kJ}{kg}

h_{out} = 459.895\,\frac{kJ}{kg}

The exit temperature of air is:

T_{out} = 457.921\,K

5 0
3 years ago
Hello how are you all bye everyone have a great day ahead​
yKpoI14uk [10]

Answer:

days good

Explanation:

because why not right

3 0
2 years ago
Read 2 more answers
My teacher wants me to build a perpetual motion machine and present it. I know they don't exist, and SHE knows they don't exist
Llana [10]

Answer:

You should do it. it is okay if it does not work because if she knows it does not exist she is using it as a example of how it don't exist

Explanation:

7 0
3 years ago
Read 2 more answers
At a certain location, wind is blowing steadily at 7 m/s. Determine the mechanical energy of air per unit mass and the power gen
Kaylis [27]

Answer:

Explanation:

From the information given;

The velocity of the wind blow V = 7 m/s

The diameter of the blades  (d) = 80 m

Percentage of the overall efficiency \eta_{overall} = 30\%

The density of air \rho = 1.25 kg/km^3

Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:

e_{mechanic} = \dfrac{mV^2}{2}

here;

m = \rho AV

= 1.25 \times \dfrac{\pi}{4}(80)^2 \times 7

= 43982.29 kg/s

∴

W = e_{mechanic} = \dfrac{mV^2}{2}

= \dfrac{43982.29 \times 7^2}{2}

= 1077566.105 \ W

\mathbf{ =1077.566 \ kW}

The actual electric power is:

W_{electric} = \eta_{overall} \times W

W_{electric} = 0.3 \times 1077.566

\mathbf{W_{electric} =323.26 \ kW}

8 0
2 years ago
La iluminación de la superficie de un patio amplio es 1600 lx cuando el ángulo de elevación del sol 53°. Calcular la iluminación
gregori [183]

Answer:

 I = 1205.69 Lx

Explanation:

The irradiation or intensity of the solar radiation on the earth is maximum for the vertical fire, with a value I₀

          I = I₀ sin θ

in this case with the initial data we can calculate the initial irradiance

         I₀ = \frac{I}{sin  \ \theta }

         I₀ = 1600 /sin 53

         I₀ = 2003.42 lx

for when the angle is θ = 37º

         I = 2003.42 sin 37

         I = 1205.69 Lx

6 0
2 years ago
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