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Ivenika [448]
3 years ago
14

Plzzzzz help me answer this question (WILL AWARD BRAINLIEST)

Chemistry
1 answer:
Greeley [361]3 years ago
5 0
The correct answer is b
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Jolene wants to experiment with sugar cubes. Which of the following causes a sugar cube to only change physically, not chemicall
Ugo [173]
If you cut the cube and keep all the pieces you are causing only physical change
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3 years ago
1. Some athletes have as little as 3.0% body fat. If such a person has a body mass of 65 kg, how many pounds of body fat does th
77julia77 [94]
1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs

65 kg  \frac{3.0 kg}{100 kg} x  \frac{2.20 lb}{1 kg} = 4.29 lbs

2. 0.94 g/mL----> 0.94 grams= 1 mL
1 Liters= 1000 mL
1kg= 1000 grams

3 Liters  \frac{1000 mL}{1 L} x   \frac{0.94 grams}{1 mL} x  \frac{1 kg}{1000 g} x   \frac{2.20 lbs}{1 kg}  = 6.20 lbs
3 0
3 years ago
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A stack of 15 pennies is immersed into a 100 mL graduate initially containing 20.6 mL of water. The volume in the graduate cylin
Gekata [30.6K]

Answer: 5.4

Explanation: The Law of Impenetrability says that two objects can't occupy the same space at the same time; therefore, the pennies and the water can't occupy the same space at the same time. Without the pennies the water level read 20.6 mL, dropping in the pennies gives a level of 26.0.

5 0
2 years ago
The equilibrium constant, Kc, for the following reaction is 5.10×10-6 at 548 K. NH4Cl(s) NH3(g) + HCl(g) Calculate the equilibri
levacccp [35]

<u>Answer:</u> The equilibrium concentration of HCl is 2.26\times 10^{-3}M

<u>Explanation:</u>

We are given:

Moles of NH_4Cl(s) = 0.564 moles

Volume of vessel = 1.00 L

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Molarity of NH_4Cl=\frac{0.564}{1}=0.564M

The given chemical equation follows:

                  NH_4Cl(s)\rightleftharpoons NH_3(g)+HCl(g)

<u>Initial:</u>         0.564

<u>At eqllm:</u>     0.564-x          x              x

The expression of K_c for above equation follows:

K_c=[NH_3][HCl]

The concentration of pure solid and pure liquid is taken as 1.

We are given:

K_c=5.10\times 10^{-6}

Putting values in above equation, we get:

5.10\times 10^{-6}=x\times x\\\\x=2.26\times 10^{-3}M,-2.26\times 10^{-3}M

Negative sign is neglected because concentration cannot be negative.

So, [HCl]=2.26\times 10^{-3}M

Hence, the equilibrium concentration of HCl is 2.26\times 10^{-3}M

5 0
3 years ago
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Sergeeva-Olga [200]

do everything
eh
t

b
b
eh


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b
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