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3 years ago

Convert the mass to kgs thanks

1 answer:

4 0

Memorize this and you'll be able to do ALL of these: 1 kg = 1,000 g

So if you have some grams, divide the number by 1,000 to get kilograms.

1,000 g = 1.000 kg

500 g = 0.500 kg

100 g = 0.100 kg

50 g = 0.050 kg

20 g = 0.020 kg

10 g = 0.010 kg

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What is a volt as applied in physics

Alexus [3.1K]

Answer:

The answer is below

Explanation:

Volt in physics is a term that is used to describe the unit of both electrical potential difference and electromotive force. In other words, it is a unit of measuring the voltage between two points. It is represented as "V".

The formula for Voltage is V=IR

Where V= Voltage, I = Current and R = Resistance.

8 0

3 years ago

An electric field of 6.1x 10^5 N/C is directed along a charge 2.9 x 10^-19 C. What

Aloiza [94]

Answer:

Electric field is a function 1/r^2

Explanation:

4 0

3 years ago

A 6.0-kg object moving at 5.0 m/s collides with and sticks to a 2.0-kg object. After the collision the composite object is movin

gogolik [260]

Answer:

a) 23 m/s

Explanation:

Assuming no external forces acting during the collision, total momentum must be conserved, as follows:

$p_{o} = p_{f} (1)$

The initial momentum p₀, can be written as follows:

$p_{o} = m_{1} * v_{1o} + m_{2}* v_{2o} = 6.0 kg * 5.0 m/s + 2.0 kg * v_{2o} (2)$

The final momentum pf, can be written as follows:

$p_{f} = (m_{1} + m_{2} )* v_{f} = 8.0 kg* (-2.0 m/s) (3)$

Since (2) and (3) are equal each other, we can solve for the only unknown that remains, v₂₀, as follows:

$v_{2o} = \frac{-6.0kg* 5m/s -8.0 kg*2.0m/s}{2.0kg} = \frac{-46kg*m/s}{2.0kg} = -23.0 m/s (4)$

This means that the 2.0-kg object was moving at 23 m/s in a direction opposite to the 6.0-kg object, so its initial speed, before the collision, was 23.0 m/s.

6 0

4 years ago

Which choice shows the correct sequence of features formed by continued wave erosion?

attashe74 [19]

Answer:

Wave-cut cliff, sea arch, sea stacks

Explanation:

The effect of a wave erosion is made obvious by the structures formed by the wave action.

The high areas of land adjacent to the incoming wave develop the early features or the formation of wave action, which includes the wave-cut cliff

The continuous undercutting of the cliff by the wave results in the formation of the wave cut platform

The effect of the wave further on a cliff, results in the formation of a sea arch and finally a sea stack

Therefore, the correct sequence is the wave-cut cliff, sea arch, sea stacks

7 0

3 years ago

An airplane, diving at an angle of 50.0° with the vertical, releases a projectile at an altitude of 554. m. The projectile hits

Valentin [98]

Answer:

Speed of the aircraft = 36.64 m/s

Explanation:

Consider the vertical motion of the projectile,

We have equation of motion s = ut+0.5at²

Let the velocity of plane be v.

Vertical velocity = vsin55 = Initial velocity of projectile in vertical direction = u

acceleration, a = 9.81 m/s²

displacement , s = 554 m

time, t = 8 s

Substituting,

554 = vsin55 x 8 +0.5 x 9.81 x 8²

v = 36.64 m/s

Speed of the aircraft = 36.64 m/s

3 0

4 years ago