The heat released by the water when it cools down by a temperature difference AT
is Q = mC,AT
where
m=432 g is the mass of the water
C, = 4.18J/gºC
is the specific heat capacity of water
AT = 71°C -18°C = 530
is the decrease of temperature of the water
Plugging the numbers into the equation, we find
Q = (4329)(4.18J/9°C)(53°C) = 9.57. 104J
and this is the amount of heat released by the water.
The answer is D . I hope this help you :) .
Answer:
both will be at liquid state. the particles will move rapidly in all directions and will collide with other particles in random motion
Answer:
3.10g
Explanation:
Please see the attached picture for the full solution.
