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Vlad [161]
3 years ago
8

Which environmental change occurs quickly

Physics
1 answer:
never [62]3 years ago
3 0
Air and water have a good day
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A Cessna aircraft has a liftoff speed of 120 km/h What minimum constant acceleration does the aircraft require to be airborne af
Lady_Fox [76]

Answer:

<h3>2.3125m/s²</h3>

Explanation:

Using the equation of motion v² = u²+2aS

v is the final velocity = 120km/hr

120km/hr = 120 * 1000/1 * 3600 = 33.3m/s

u is the initial velocity = 0m/s

a is the acceleration

S is the distance covered = 240m

On substituting the given parameters

33.3² = 0²+2a(240)

33.3² = 480a

1110 = 480a

a = 1110/480

a = 2.3125m/s²

Hence the minimum constant acceleration that the aircraft require to be airborne after a takeoff run of 240 m is 2.3125m/s²

4 0
3 years ago
The load across a 12 V battery consists of a series combination of three resistors 34 Ω, 42Ω, and 30Ω. What is the total resista
stira [4]

Answer:

The total resistance is 106 Ω and the current in the circuit is 0.11 A.

Explanation:

Given that,

Voltage of the battery, V = 12 V

Resistors 34 Ω, 42Ω, and 30Ω are connected in series.

The total resistance is given by :}

R = 34 + 42 +30

= 106Ω

Let I is the total current in the circuit. Using ohm's law to find it such that,

I=\dfrac{V}{R}\\\\I=\dfrac{12}{106}\\\\I=0.11\ A

Hence, the total resistance is 106 Ω and the current in the circuit is 0.11 A.

4 0
3 years ago
A rubber band has a spring constant of 45 N/m. A classmate stretches it a length of 0.2 m before firing it at Mr. C. Ouch. Calcu
nata0808 [166]

Answer:

<h2>0.9 Joules</h2>

Explanation:

Elastic potential energy of a spring= 1/2 × Spring constant × displacement²

following calculations you will get ur answer!!

5 0
3 years ago
Please help. 25 POINTS, PLEASE ANSWER PROMPTLY
Anvisha [2.4K]

Answer:

D

Explanation:

7 0
3 years ago
An object is moving in a straight line. At t = 0, its speed is 5.0 m/s. From t = 0 to t = 5.0 s, its acceleration is 2.5 m/s2. F
bagirrra123 [75]

Answer:

v1 = a t + v0 = 2.5 * 5 + 5 = 17.5 m/s after 5 sec

v2 = o * 6 + 17.5 = 17.5 m/s after 11 sec

S1 = V0 t + 1/2 a t^2 = 5 * 5 + 1.25 * 5^2 = 56.25 m

S2 = 17.5 * 6 = 105 m

S = 56.3 + 105 = 161 m

Vav = S / t = 161 m / 11 s = 14.6 m/s

3 0
3 years ago
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