The answer is C- air resistance
Answer:
533.92 m/s
Explanation:
The root-mean-square speed of a gas is given by v = √(3RT/M)
R = molar gas constant = 8.3145 J/mol-K
T = Temperature = 320 K
M = Molar mass of Nitrogen in kg/mol = 2 × 14 × 10⁻³ kg/mol = 28 × 10⁻³ kg/mol
v = √(3RT/M) = √(3 × 8.3145 J/mol-K × 320 K/28 × 10⁻³ kg/mol) = √7981920/28 = √285.068.57 = 533.92 m/s
Answer:
E = q V B describes the electric field induced
E Proportional to V B
while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)
If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly
When V drops to zero the deflection must again be zero
So one would see a blip due to the deflection of the galvanometer
Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)
B always increases to a constant value because of the properties of the magnet.
Answer:
9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.
Explanation:
In this exercise we need to determined the sensible heat store in a kilogram of concrete due to a change in temperature. Sensible heat (
), measured in kilojoules, is defined by the following expression:
(1)
Where:
- Mass, measured in kilograms.
- Average specific heat of concrete, measured in kilojoules per kilogram-degree Celsius.
, 
- Initial and final temperatures of concrete, measured in degrees Celsius.
If we know that 
, 
, 
and 
, then the energy store in a kilogram of concrete is:
9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.
