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elena-s [515]
3 years ago
7

An object of mass 3.05 kg, moving with an initial velocity of 5.09 i m/s, collides with and sticks to an object of mass 2.34 kg

with an initial velocity of -3.28 j m/s. find the final velocity of the composite object.
Physics
1 answer:
Irina18 [472]3 years ago
3 0
Try using the G.U.E.S.S method. Which is G for givens which you write down all the information it gives you in the problem. U for the unknown like what are you trying to find/what the question asking for. E for equation find the right formula that best fits this problem. S for substitute so plug in the numbers given in the problem into the formula that best fits. The last S is solve which you workout the equation to find what the question is asking for. Hope this helps :)
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SpyIntel [72]

Explanation :

It is given that, the driver accelerates from a stop sign, cruises for 20 s at a constant speed of 60 km/h, and then brakes to come to a stop 40 s after leaving the stop sign.

We know that acceleration is defined as the rate of change of velocity.

a=\dfrac{dv}{dt}

Where

dv is the change in velocity, dv = 0 - 60 m/s = -60 m/s

dt is the change in time, dt = 40 s - 30 s = 10 s

So, a=\dfrac{-60\ m/s}{10\ s}

a = -6\ m/s^2

From the graph it is clear that, from 30 s to 40 s the car is decelerating. So, at every second within this time the value of acceleration will be same i.e. -6\ m/s^2.

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Which product of nuclear decay has mass but no charge?
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2 years ago
When 597 J of heat are added to a gas, it expands. Its internal energy increases by 318 J. How much work does the gas do? (Unit=
damaskus [11]

The magnitude of work done by the gas is 279 J and the sign is negative so W = -279 J as work is done by the system.

<u>Explanation:</u>

According to first law of thermodynamics, the change in internal energy of the system is equal to the sum of the heat energy added or released from the system with the work done on or by the system. If the heat energy is added to the system to perform a certain work, then the heat energy is taken as positive, while it will be negative when the heat energy is released from the system.

Similarly, in this case, the heat energy of 597 J is added to the system. So the heat energy will be positive, while the gas expansion occurs means work is done by the system.

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Since ΔU is the change in internal energy which is given as 318 J and the heat energy added to the system is Q = 597 J.

Then the work done by the gas = ΔU - Q = 318 J - 597 J = - 279 J.

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