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mylen [45]
3 years ago
5

NH4CO2NH2(s) equilibrium reaction arrow 2 NH3(g) + CO2(g) Ammonium carbamate decomposes according to the equation above. At 40°C

, an equilibrium mixture for this reaction contains 0.0640 atm CO2 and 0.370 atm NH3. What is the value of the equilibrium constant Kp for the reaction?
Chemistry
1 answer:
V125BC [204]3 years ago
4 0

Answer:

Kp = 8.76×10⁻³

Explanation:

We determine the carbamate decomposition in equilibrium:

NH₄CO₂NH₂ (s) ⇄ 2NH₃(g) + CO₂(g)

Let's build the expression for Kp

Kp = (Partial pressure NH₃)² . Partial pressure CO₂

We do not consider, the carbamate because it is solid and we only need the partial pressure from gases

Kp = (0.370atm)² . 0.0640 atm

Kp = 8.76×10⁻³

Remember Kp does not carry units

 

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Given 50.0 grams of Strontium, find grams of Phosphorus required for complete reaction
Sveta_85 [38]

Answer:

                     Mass = 11.78 g of P₄

Explanation:

                     The balance chemical equation is as follow:

                                          6 Sr + P4 → 2 Sr₃P₂

Step 1: Calculate moles of Sr as;

Moles = Mass / M/Mass

Moles = 50.0 g / 87.62 g/mol

Moles = 0.570 moles

Step 2: Find moles of P₄ as;

According to equation,

6 moles of Sr reacted with  =  1 mole of P₄

So,

0.570 moles of Sr will react with  =  X moles of P₄

Solving for X,

X = 1 mol × 0.570 mol / 6 mol

X = 0.0952 mol of P₄

Step 3: Calculate mass of P₄ as,

Mass = Moles × M.Mass

Mass = 0.0952 mol × 123.89 g/mol

Mass = 11.78 g of P₄

8 0
3 years ago
Light travels at a speed of 3.00 × 1010 cm/sec. What is the speed of light in kilometers/hour?
snow_lady [41]

Answer:

300,000km is the speed of light

4 0
3 years ago
The combustion of ammonia in the presence of excess oxygen yields no2 and h2o: 4 nh3 (g) + 7 o2 (g) â 4 no2 (g) + 6 h2o (g) the
VLD [36.1K]
The answer would be 118.68 g.
Explanation for this is:4 moles of NH3 give 4 moles of NO2 
so 1mole of NH3 will give 1 mole of NO2 
43.9 grams of NH3 contains 2.58 moles 
so 2.58 moles will be produced of NO2 
which is 118.7 grams this the amount of oxygen that is used.
8 0
3 years ago
Which radioisotopes have the same decay mode and have half-lives greater than
AveGali [126]

The correct answer is (3)


I-131 and P-32


The explanation:


according to attached table:


- we can see that the half life of p 32 is 14.28d (more than one hour)

- and the half life of I-131 is 8.021 d (more than one hour)


and They both have β- decay mode and with half-lives greater than hour.


4 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK AS POSSIBLE!!!!
GalinKa [24]

Answer:

4180J

Explanation:

(25.0g)(4.184J/g°C)(75°C-35.0°C)

(25.0g)(40.0°C)(4.184J/g°C)

(1.00*10³g°C)(4.184J/g°C) = 4184J

use sig figs:

4180J

8 0
3 years ago
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