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mylen [45]
3 years ago
5

NH4CO2NH2(s) equilibrium reaction arrow 2 NH3(g) + CO2(g) Ammonium carbamate decomposes according to the equation above. At 40°C

, an equilibrium mixture for this reaction contains 0.0640 atm CO2 and 0.370 atm NH3. What is the value of the equilibrium constant Kp for the reaction?
Chemistry
1 answer:
V125BC [204]3 years ago
4 0

Answer:

Kp = 8.76×10⁻³

Explanation:

We determine the carbamate decomposition in equilibrium:

NH₄CO₂NH₂ (s) ⇄ 2NH₃(g) + CO₂(g)

Let's build the expression for Kp

Kp = (Partial pressure NH₃)² . Partial pressure CO₂

We do not consider, the carbamate because it is solid and we only need the partial pressure from gases

Kp = (0.370atm)² . 0.0640 atm

Kp = 8.76×10⁻³

Remember Kp does not carry units

 

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An isotope of lead can be represented by the following symbol ²⁰⁷ 82 PB. From this symbol, it can be deduced that one atom of th
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Answer:

B) 82 protons

Explanation:

The number of protons for an element never change. 82 Is the atomic number for Pb which is how many protons it has. An isotope means it has more neutrons.

6 0
3 years ago
Someone please help me sort these out for either if they are Heterogenous, solution, suspension, or colloid. Tuna casserole, gre
Sphinxa [80]
Heterogeneous-a mixture of two or more things
solution-a substance that dissolves
suspension-mixture where solid particles do not dissolve
colloid-does not settle and cannot be seperated

Heterogeneous
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Solution
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Colloid
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7 0
3 years ago
If a substance has a half-life of 55.6 s, and if 230.0 g of the substance are present initially, how many grams will remain afte
Assoli18 [71]

Answer:

m=0.127g

Explanation:

Hello,

In this case, for a first-order reaction, we can firstly compute the rate constant from the given half-life:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{55.6s}=0.0125s^{-1}

In such a way, the integrated first-order law, allows us to compute the final mass of the substance once 10.0 minutes (600 seconds) have passed:

m=m_0*exp(-kt)=230.0g*exp(-0.0125s^{-1}*600s)\\\\m=0.127g

Best regards.

6 0
3 years ago
Draw the alkyl bromide(s) you would use in a malonic ester synthesis of ethyl 3-methylbutanoate.
Gennadij [26K]

The structure of the alkyl bromides used in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate.

Ethyl 2-methyl-4-pentenoate by Malonic ester synthesis.

The alkylation of diethyl malonate or a related ester of malonic acid at the carbon alpha (immediately next) to both carbonyl groups, followed by conversion to a substituted acetic acid, characterizes the chemical reaction known as the malonic ester synthesis.

As a result, it is evident from the structure of ethyl 2-methyl-4-pentenoate that ethyl and methyl bromides are the alkyl bromides employed.

To learn more about Malonic ester synthesis refer here:

brainly.com/question/17237043

#SPJ4

4 0
1 year ago
The density of a rock that was a mass of 454 grams and a volume of 100 cm3
puteri [66]

Answer:

The answer is

<h2>4.54 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass of rock = 454 g

volume = 100 cm³

The density of the rock is

density =  \frac{454}{100}  =  \frac{227}{50}  \\

We have the final answer as

<h3>4.54 g/cm³</h3>

Hope this helps you

3 0
2 years ago
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