Pure substances are made of the same material and have almost the same properties such as: Carbon, Iorn, Water, Sugar, Salt, and Nitrogen.
Answer:
O2, oxygen.
Explanation:
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In this case, for the undergoing chemical reaction, we need to compute the moles of CO2 yielded by 85 g of CH4 (molar mass = 16 g/mol) and by 320 g of O2 (molar mass 32 g/mol) via the following mole-mass relationships:
Considering the 1:2:1 among CH4, O2 and CO2. Therefore, since 320 g of O2 yield the smallest amount of CO2 we infer that the limiting reactant is O2.
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A mole is equal to 6.02x10^23, so one mole of H2O has 6.02x10^23 water molecules. To get how many of them are in 6 moles you need to multiple it by six:
(6.02x10^23)x6= 3.612x10^24
So, there’s 3.612x10^24 water molecules in 6 moles of water
Answer:
D) 0 k.cal per 4 grams
Explanation:
Genarally, glucose can be classified into two enantiomers such as d-glucose and l-glucose. The d-glucose is the most common sugar that bodies of living organisms use as source of energy. However, l-glucose is an organic compound and it is one of the aldohexose monosaccharides. It is the l-isomer of glucose and commonly refer to as a low-calorie sweetener. The l-glucose is relatively indistinguishable in taste from d-glucose but cannot be used as a source of energy. Therefore, in the given problem:
if d-glucose has an estimated caloric value of 1 k.cal per 4 grams of carbohydrate, then the caloric value of l-glucose will be 0 k.cal per 4 grams.
