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statuscvo [17]
2 years ago
5

ladders are not required to be inspected for visible defects prior to the first use of each work shift,and after any occuurrence

that could affect their safety.. True or False?​
Engineering
1 answer:
zaharov [31]2 years ago
4 0

Answer:

The answer is False.

Explanation:

When it comes to occupational safety,<em> it is very important for ladders to be inspected by a qualified person before each use.</em> This is because ladders undergo conditions that impact their integrity while being in use. The inspection is also essential in order for the ladder to be timely replaced.

<u><em>Ladder accidents or ladder-related injuries happen every year.</em></u> Around 700 occupational deaths due to elevated fall from a ladder accounts for 15% of all occupational deaths. Misuse or damage ladders are often the reasons for this.

Thus, the answer in the above statement is False because ladders are required to be inspected for visible defects prior to the first use of each work shift and after any occurrence that could affect their safety.

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Both are right

Explanation:

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1 year ago
A lightweight electric car is powered by ten 12-V batteries. At a speed of 100 km/h, the average frictional force is 1500 N. Wha
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Answer:41.67kW

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A heat pump cycle is used to maintain the interior of a building at 15°C. At steady state, the heat pump receives energy by heat
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Answer:

a) Ql=33120000 kJ

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c) COPreversible= 29.3

Explanation:

a) of the attached figure we have:

HP is heat pump, W is the work supplied, Th is the higher temperature, Tl is the low temperature, Ql is heat supplied and Qh is the heat rejected. The worj is:

W=Qh-Ql

Ql=Qh-W

where W=2000 kWh

Qh=120000 kJ/h

Q_{l}=14days(\frac{24 h}{1 day})(\frac{120000 kJ}{1 h})-2000 kWh(\frac{3600 s}{1 h})=33120000 kJ

b) The coefficient of performance is:

COP=\frac{Q_{h} }{W}=\frac{120000 kJ/h*14(\frac{24 h}{1 day}) }{2000 kWh(\frac{3600 s}{1 h}) } = 5.6

c) The coefficient of performance of a reversible heat pump is:

COP_{reversible}=\frac{T_{h} }{T_{h}-T_{l}  }

Th=20+273=293 K

Tl=10+273=283K

Replacing:

COP_{reversible}=\frac{293}{293-283}=29.3

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