Explain what the engineering team should advise in the following scenario.
1 answer:
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Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:
The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
- Nitrogen gas:
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank: = 142.85mols
- Carbon Dioxide:
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank: = 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:
For Nitrogen gas:
= 0.6
For Carbon Dioxide:
0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Answer:
the required expression is = 4[ 1 -
]
Explanation:
Given the data in the question;
Q = -0.2[ 1 - ]
ω = 100 rad/s
Torque T = 18 N-m
Electric power input = 2.0 kW
now, form the first law of thermodynamics;
dE/dt = dQ/dt + dw/dt = Q' + w'
dE/dt = Q' + w' ------ let this be equation 1
w' is the net power on the system
w' = -
= T × ω
we substitute
= 18 × 100
= 1800 W
= 1.8 kW
so
w' = -
w' = 2.0 kW - 1.8 kW
w' = 0.2 kW
hence, from equation 1, dE/dt = Q' + w'
we substitute
dE/dt = -0.2[ 1 - ] + 0.2
dE/dt = -0.2 + 0.2 ] + 0.2
dE/dt = 0.2
Now, the change in total energy, increment E, as a function of time;
ΔE =
ΔE =
ΔE =
= 4[ 1 -
]
Therefore, the required expression is = 4[ 1 -
]