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lawyer [7]
4 years ago
9

Two dimensional motion is not always projectile motion. In two dimensional motion that is not projectile motion, what is not acc

elerating the object
Physics
2 answers:
tigry1 [53]4 years ago
5 0

Two dimensional motion is not always projectile motion. In two dimensional motion that is not projectile motion, gravity is not accelerating the object

MatroZZZ [7]4 years ago
4 0

gravity is the correct answer.

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A dog can hear sounds in the range from 15 to 50,000 hz. what wavelength corresponds to the lower cut-off point of the sounds at
Ira Lisetskai [31]
The frequency corresponding to the lower cut-off point is 
f=15 Hz
The speed of sound at a temperature of 20^{\circ}C is approximately
v=343 m/s

Therefore we can use the relationship between speed of a wave, frequency and wavelength to calculate the corresponding wavelength:
\lambda= \frac{v}{f}= \frac{343 m/s}{15 Hz}=22.87 m
So, the corresponding wavelength is 22.87 m.
3 0
3 years ago
A satellite moves in a circular earth orbit that has a radius of 7.49 x 106 m. A model airplane is flying on a 24.1-m guideline
mina [271]

Answer:

Explanation:

Given

radius of satellite orbit r_1=7.49\times 10^6 m

And orbital velocity is given by

v=\sqrt{\frac{GM}{r}}

where M=mass of earth =5.98 \times 10^{24} kg

G=6.67\times 10^{-11}

v=\sqrt{\frac{6.67\times 10^{-11}\times 5.98\times 10^{24}}{7.49\times 10^6}

v=7.29 \times 10^3 m/s

centripetal acceleration is given

a_c=\frac{v^2}{r}

a_c=\frac{(7.29\times 10^3)^2}{7.49\times 10^6}

a_c=7.095 m/s^2

For Model airplane

a_c=\frac{v^2}{r}

7.095=\frac{v^2}{24.1}

v=\sqrt{170.98}=13.07 m/s

4 0
4 years ago
Which statement accurately describes what happens when water turns to ice in terms of energy
Deffense [45]

Answer:

The water releases energy which causes the water molecules to have less kinetic and potential energy, changing their configuration from liquid to solid.

Explanation:

Confirmed through test.

7 0
4 years ago
PLS HELP! What is the gravitational field strength on the moon?
astra-53 [7]

The gravitational field strength on the moon is \frac{1}{6} of the gravitational field strength on the earth

<u>On the earth:</u>

the gravitational field strength (g) is determined as:

g=G\frac{m}{r^2}

where:

  • G: the gravitational constant
  • m: the mass of the earth
  • r: the radius of the earth

g=9.8 N/kg = 9.8 m/s^2

<u>Then on the moon:</u>

g=[tex]\frac{1}{6}*9.8=1.6 N/kg[/tex]

<u>The answer will be</u> : A.1.6 N/kg

<u />

5 0
4 years ago
Which of the following can be measured in seconds<br> Acceleration<br> Speed<br> Time<br> Distance
Scrat [10]

Answer:

time

<u>Explanation</u><u> </u>

the answer is time

5 0
3 years ago
Read 2 more answers
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