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Lesechka [4]
4 years ago
8

If f(x)=3^x and g(x)=2x+5, at which value of x is f(x)

Mathematics
1 answer:
tester [92]4 years ago
4 0
2

This is because f(2)=9 since 3^2=9
&
G(2)=9 since 2(2)+5=9
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Which term describes how the two sides of this figure are related?
DochEvi [55]

Answer:

The answer is A - symmetry.

None of the other options really have bearing in relation to the question.

Hope this helps.

Step-by-step explanation:

5 0
3 years ago
A telephone company charges a fixed monthly rate plus a rate per minute of usage. The company charges $120 for 100 minutes of us
Alecsey [184]
<h2>Answer</h2>

Draw a graph which joins the points (100, 120) and (50, 95) and has a slope = 0.50

<h2>Explanation</h2>

A graph of y against x means that x is the independent variable and y is the dependent variable. Notice that the charge (y) depends on the number of minutes (x). Therefore, the points that we are going to join to make our graph will have coordinates (x, y)

We know that the company charges $120 for 100 minutes, so x=100 and y=120. Therefore, our first point will be (100, 120)

We also know that the company charges $95 for 50 minutes, so x=95 and y=50. Therefore, our second point will be (50, 95)

Now, to find the slope between our tow points, we are going to use the slope formula: m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

where

(x_{1},y_{1}) are the coordinates of the first point

(x_{2},y_{2}) are the coordinates of the second point

We know from our points that x_{1}=100, y_{1}=120, x_{2}=50, and y_{2}=95. So let's replace those values in our formula to find m

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{95-120}{50-100}

m=\frac{-25}{-50}

m=\frac{1}{2}

m=0.50

Now that we have our slope, we can use the point-slope formula to complete the equation of the line joining our two points

y-y_{1}=m(x-x_{1})

y-120=0.50(x-100)

y-120=0.50x-50

y=0.50x+70

7 0
3 years ago
Read 2 more answers
How do you turn 55 into a fraction
kifflom [539]
55/1, see previous answer.
8 0
4 years ago
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Help me plz i need help
Oxana [17]

Answer:

y-2.0

x-2.3

Step-by-step explanation:

hope it help

8 0
2 years ago
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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
yKpoI14uk [10]

Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
4 years ago
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