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3 years ago

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which describes the magnetic field that forms when a wire carries an electric current? a. It is in a line perpendicular to the w

ire. b. It is in a line parallel with the wire. c. It is in a cylinder around the wire. d. It is in a cylinder across the wire.

2 answers:

frez [133]3 years ago

5 0

C. the magnetic field is shaped like a cylinder through which the wire is positioned along the axis of symmetry.

True [87]3 years ago

4 0

Answer:

Option (c)

Explanation:

According to the Maxwell's right hand rule, If we hold a current carrying conductor in our right hand, such that the thumb indicates the direction of current flowing in the conductor then the curling of fingers gives the direction of magnetic field around the conductor.

So, the magnetic field around the conductor is in cylindrical form around the wire.

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Three long parallel wires each carry 2.0-A currents in the same direction. The wires are oriented vertically, and they pass thro

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$21.2\times 10^{-6}$ T

Explanation:

$i$ = magnitude of current in each wire = 2.0 A

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$B = (10^{-7}) \left ( \frac{2(2)}{0.04} \right )$

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$B'$ = magnitude of magnetic field by wire at B

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Net magnitude of the magnetic field at D is given as

$B_{net} = \sqrt{B^{2}+B^{2}} + B'$

$B_{net} = \sqrt{2} B + B'$

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Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2

liubo4ka [24]

Answer:

The volume of the larger cube is 5.08 g/cm³.

Explanation:

Given that,

Mass of smaller cube = 20 g

Density of smaller cube $\rho= 7.87 g/cm^2$

Dylan has two cubes of iron.

The larger cube has twice the mass of the smaller cube.

$M_{l}=2m_{s}$

Density is same for both cubes because both cubes are same material.

The density is equal to the mass divided by the volume.

$\rho=\dfrac{m}{V}$

$V=\dfrac{m}{\rho}$

Where, V = volume

m = mass

$\rho=density$

We need to calculate the volume of smaller mass

The volume of smaller mass

$V_{s}=\dfrac{m_{s}}{\rho_{s}}$

$V_{s}=\dfrac{20}{7.87}$

$V_{s}=2.54\ cm^3$

Now, We need to calculate the volume of large cube

$V_{l}=\dfrac{m_{l}}{\rho_{l}}$

$V_{l}=\dfrac{2\times20}{7.87}$

$V_{l}=5.08\ g/cm^3$

Hence, The volume of the larger cube is 5.08 g/cm³.

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3 years ago