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Elanso [62]
3 years ago
13

What is the KE of a bicycle with a mass of 41kg traveling at a velocity of 8 m/s ?

Physics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

What is the kinetic energy of a bicycle with a mass of 14 kg traveling at a velocity of 3 m/s? Physics ... K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

1 answer  

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

Explanation:

K=12mv2=12×14 kg × (3 m/s)2=63 Joule.

63 Joule Explanation: K=12mv2=12×14 kg × (3 m/s)2=63 Joule

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What is the correct answer?
sashaice [31]

Answer:

D) 4

Explanation:

Roots of a polynomial must be factors of the last term.

In this case, the factors of 6 are +1, -1, +2, -2, +3, -3, +6, -6. The only factor that doesn't show up, given the options, is 4. This means that D is the correct answer.

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Three oxygen isotopes
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Which option correctly describes a model of methanol. URGENT
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The last one.

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A bowling ball of mass 5.8 kg moves in a straight line at 4.34 m/s How fast must a Ping-Pong ball of mass 2.214 g move in a stra
lilavasa [31]

Answer: 11369.46 m/s

Explanation:

We have the following data:

m_{1}=5.8 kg is the mass of the bowling ball

V_{1}=4.34 m/s is the velocity of the bowling ball

m_{2}=2.214 g \frac{1 kg}{1000 g}=0.002214 kg is the mass of the ping-pong ball

V_{2} is the velocity of the ping-pong ball

Now, the momentum p_{1} of the bowling ball is:

p_{1}=m_{1}V_{1} (1)

p_{1}=(5.8 kg)(4.34 m/s)  

p_{1}=25.172 kg m/s (2)

And the momentum p_{2} of the ping-pong ball is:

p_{2}=m_{2}V_{2} (3)

If the momentum of the bowling ball is equal to the momentum of the ping-pong ball:

p_{1}=p_{2} (4)

m_{1}V_{1}=m_{2}V_{2} (5)

Isolating V_{2}:

V_{2}=\frac{m_{1}V_{1}}{m_{2}} (6)

V_{2}=\frac{25.172 kg m/s}{0.002214 kg} (7)

Finally:

V_{2}=11369.46 m/s

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