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kotykmax [81]
3 years ago
9

Which of the following is an observation and not an inference?. a.. A cup with steam coming from it will be hot to the touch.. b

.. Dark clouds in the sky will mean rain later in the afternoon.. c.. Bubbles form when two chemicals are mixed together.. d.. A plastic bag moving along the ground is being pushed by the wind.
Physics
2 answers:
horrorfan [7]3 years ago
5 0

ANSWER IS: C

Which of the following is an observation and not an inference?

a.

A cup with steam coming from it will be hot to the touch.

b.

Dark clouds in the sky will mean rain later in the afternoon.

<u>c. </u>

<u>Bubbles form when two chemicals are mixed together. </u>

d.

A plastic bag moving along the ground is being pushed by the wind.

I TOOK THE TEST

nata0808 [166]3 years ago
3 0
The correct answer from the list of choices is option C. An example of an observation is when bubbles formed when two chemicals are mixed together. It is an observation because it is what is seen directly by the naked eye after mixing the chemicals.
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An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if
N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]  

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.  

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.  

I hope this helps!

Explanation:

8 0
3 years ago
Find a) molar fraction, b) concentration in mol / and c) concentration in mol / kg of an aqueous solution with 25% alcohol: the
igor_vitrenko [27]

Explanation:

Answer

( 58.3 mL ) (

0.789 g

1 mL

) (

1 mole

46 g

) = 1 mole C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) (

1 mole

18 g

) = 27.8 mole H2O

The total moles = 1 mole C2H5OH + 27.8 mole H2O = 28.8 moles

The mole fraction =

moles C2H5OH

total moles

=

1 mole C2H5OH

28.8 total moles

= 0.035

The mole percent would be 3.5%.

What is the weight fraction?

Answer

( 58.3 mL ) (

0.789 g

1 mL

) = 46 g C2H5OH

( 500 mL H2O ) (

1 g

1 mL

) = 500 g H2O

The total mass = 46 g C2H5OH + 500 g H2O = 546 g

The mass fraction =

mass C2H5OH

total mass

=

46 g C2H5OH

546 total grams

= 0.084

The mass percent would be 8.4%.

What is the molarity?

Answer

The molarity =

moles C2H5OH

L of solution

=

1 mole C2H5OH

.5583 L

= 1.79 M

What is the molality?

Answer

The molality =

moles C2H5OH

kg of solvent

=

1 mole C2H5OH

0.5 kg H2O

= 2

8 0
3 years ago
Absolute zero (K=0 or -273.15°C) is what temperature on the Farenheit scale? a) 459.4°F b) -301.43 °F c) 233.05°F d) -40.15°F e
ANEK [815]

Answer:

e) None of these is true

Explanation:

Given that

Temperature = 0 K

We know that relationship between kelvin and Farenheit scale

\dfrac{K-273}{100}=\dfrac{F-32}{180}

Now by putting the values

\dfrac{K-273}{100}=\dfrac{F-32}{180}

\dfrac{0-273}{100}=\dfrac{F-32}{180}

So F= - 459.67°F

So we can say that 0 K is equal to  - 459.67°F.

So the our option e is correct.

3 0
4 years ago
Radiation from the Sun reaching Earth (just outside the atmosphere) has an intensity of 1.4 kW/m2. (a) Assuming that Earth (and
baherus [9]

To solve the problem we will require the concept of Force as a definition of pressure and Area, and the concept of light pressure itself determined by the relationship between intensity and the speed at which light travels. We will match the terms and find the desired force value,

F = PA

Here,

P = Pressure

A = Area

Pressure due to the light of the sun will be

P= \frac{I}{c}

Here,

I = Intensity

c = Speed velocity

Equation both therms we have that

F = \frac{IA}{c}

We have a circular area then

F = \frac{I(\pi r^2)}{c}

Replacing with our values (Adding the radius of the Earth)

F = \frac{(1.4*10^3W/m^2)(\pi (6.32*10^6m)^2)}{3.0*10^8m/s}

F = 6.0*10^8N

Therefore the Force on Earth due to radiation pressure is 6*10^8N

4 0
3 years ago
Consider a metal bar of initial length L and cross-sectional area A. The Young's modulus of the material of the bar is Y. Find t
RUDIKE [14]

Answer:

Spring constant = YA / L

Explanation:

Let F be the force being applied on cross sectional area A of metal bar due to which an extension of ΔL is obtained in the wire of length L then

stress = F / A

strain = ΔL /L

Young's modulus = ( F / A ) / (ΔL /L)

Y = ( F L / A ΔL )

( F / ΔL ) = ( YA / L )

Spring constant = ( F / ΔL )

Spring constant = YA / L

6 0
3 years ago
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