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STALIN [3.7K]
3 years ago
14

According to solubility rules, which of the following compounds is soluble in water?

Chemistry
1 answer:
Nata [24]3 years ago
6 0
The answer is A hope this help
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The solubility of lead(ii) chloride is 0.45 g/100 ml of solution. what is the ksp of pbcl2? 4.9 × 10-2 1.7 × 10-5 8.5 × 10-6 4.2
Artyom0805 [142]
Answer:
1.7 * 10^-5

Explanation:
1- get the number of moles of PbCl2:
number of moles = mass / molar mass
number of moles = 0.45 / 278.1 = 1.618 * 10^-3 moles

2- get the concentration of Pb2+:
molarity = number of moles of solute / volume of solution in liters
molarity = (1.618 * 10^-3) / (0.1) = 0.0162 M

3- getting concentration of Cl-:
<span>PbCl2(s) <==> Pb2+(aq) + 2Cl-(aq) 
</span>We can note that:
For a certain amount of Pb2+ formed, twice this amount of Cl- is formed.
This means that:
for 0.0162 M of Pb2+, 2*0.0168 = 0.0324 M of Cl- is formed

4- getting Ksp:
Ksp = [Pb2+][Cl-]²
Ksp = (0.0162)*(0.0324)²
Ksp = 1.7 * 10^-5

Hope this helps :)
7 0
4 years ago
For the following unbalanced equation: Cu(s) + AgNO₃(aq) ➞ Cu(NO₃)₂(aq) + Ag(s) if 1.50 moles of copper and 3.00 moles of silver
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3 years ago
Is facilitated diffusion passive or active transport?
bazaltina [42]

Answer:

Its passive

Explanation:

Facilitated diffusion is a type of passive transport that allows substances to cross membranes with the assistance of special transport proteins.

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Two processes are described below: Process A: rapid moving water strikes a rock on the bottom of a stream and breaks it into pie
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both represent physical  weathering

Explanation:

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