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3 years ago

Are protons positive and neutrons neutral

Chemistry

1 answer:

Elis [28]3 years ago

3 0

Answer: Yes, they're neutral.

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How much (mL) of a 2.0 M sodium hydroxide solution would it take to neutralize 50 mL of a 6.0 M solution of hydrochloric acid?

Tom [10]

Answer:

150ml

Explanation:

For this question,

NaOH completely dissociates. It is a strong base

HCl also completely dissociates. It is a strong acid

So we have this equation

m1v1 = m2v2 ----> equation 1

M2 = 2m

V1= ??

M2 = 6m

V2 = 50m

When we input these into equation 1, we have:

2m x v1 = 6m x 50ml

V1 = 6m x 50ml/2

V1 = 300/2

V1 = 150ml

Therefore NaOH that is required to neutralize the solution of hydrochloric acid is 150ml.

Thank you

8 0

2 years ago

Two fossils with reptilian characteristics are part of a shipment of fossils sent to a museum. The only difference is that one o

SOVA2 [1]

The one with feather. because it was probably form the Dino era

5 0

3 years ago

How many moles of carbon monoxide are required to react completely with 1.75 mol of iron oxide what is what you need to given in

Alborosie

Moles oxide molecules molecules that molecules the molecules are used in the same molecules and the

7 0

3 years ago

Calculate Srxn for the equation below. (Round to the nearest whole number.)

zaharov [31]

Answer:The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.

Explanation:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g),\Delta S_{rxn}=?$

$=192.8 J/mol K$

$\Delta S_{O_2}=205.0 J/mol K$

$\Delta S_{H_2O}=188.83 J/mol K$

$\Delta S_{NO}=210.8 J/mol K$

$\Delta S_{rxn}=(4 mol\times \Delta S_{NO}+6 mol\times \Delta S_{H_2O})-(4 mol\times \Delta S_{NH_3}-5 mol\times \Delta S_{O_2})$

$\Delta S_{rxn}=(4\times 210.8 J/mol K+6\times 188.83 J/mol K)-(4\times 192.8 J/mol K+5\times 205.0 J/mol K)$

$\Delta S_{rxn}=179.98 J/K$

The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.

4 0

3 years ago

A liquid that occupies a volume of 0.820 L has a mass of 2.56 kg.

user100 [1]

Answer:

The density of this liquid is 0.320 kg/L

Explanation:

Given:

Volume of the Liquid = 0.820 L

Mass of the liquid = 2.56 kg.

To Find:

The density of the liquid in kg/L

Solution:

Density is the mass occupied by the substance in unit volume. This density is essential determining whether the substance floats or sinks. Greek letter(rho) is used to denote density

The equation of for density is

$Density = \frac{mass}{volume}$

$\rho = \frac{m}{v}$

where m is the mass

v is the volume

On substituting the given values

$\rho = \frac{0.820 }{2.56}$

$\rho = 0.320 kg/L$

7 0

3 years ago