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3 years ago

Calculate Srxn for the equation below. (Round to the nearest whole number.)

Chemistry

1 answer:

zaharov [31]3 years ago

4 0

Answer:The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.

Explanation:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g),\Delta S_{rxn}=?$

$=192.8 J/mol K$

$\Delta S_{O_2}=205.0 J/mol K$

$\Delta S_{H_2O}=188.83 J/mol K$

$\Delta S_{NO}=210.8 J/mol K$

$\Delta S_{rxn}=(4 mol\times \Delta S_{NO}+6 mol\times \Delta S_{H_2O})-(4 mol\times \Delta S_{NH_3}-5 mol\times \Delta S_{O_2})$

$\Delta S_{rxn}=(4\times 210.8 J/mol K+6\times 188.83 J/mol K)-(4\times 192.8 J/mol K+5\times 205.0 J/mol K)$

$\Delta S_{rxn}=179.98 J/K$

The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.

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The electron configuration of an element is shown below.

gayaneshka [121]

Answer:it is in group 7

Explanation:it is in this group because in the increasing number of atomic number the element is found in group seven. The element is likely to receive 3 electrons while bonding with another element to make it stable.

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2 years ago

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Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a

dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is $_2^4\textrm{He}$

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = $6.64648\times 10^{-24}g$

Mass of 1 electron = $9.10939\times 10^{-28}g$

Calculating the mass contributed by the nucleus = $m_{He}-2(m_e)$

Mass of the nucleus of He-4 atom = $6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}$

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}$

Putting values in above equation, we get:

$\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99$

Hence, the fraction of atom's mass contributed by nucleus is 0.99

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3 years ago

What are six forms of energy? Find an example of each.

Evgesh-ka [11]

1-Electric Energy
Example: A lightbulb is an example of electric energy
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Example: When a dog barks, that is sound energy
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Example: When we use the sun for energy. Like using it to dry our clothes.
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3 years ago

What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a

Alexandra [31]

144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K [At STP]

Now first find the number of moles

F₂ + CaBr₂ → CaF₂ + Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So, 199.89 g CaBr₂ reacts with = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

$n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}$

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

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1 year ago

Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. (1.8 x 1

slamgirl [31]

Answer : The answer is, $0.2\times 10^{-4}$

Explanation :

Scientific notation : It is defined as the way or representation of expressing the number that are too big or too small that is written in the decimal form. That means always written in the power of 10 form.

For example : 8000 is written as, $8.0\times 10^3$ in this notation, the significant figure is, 1 but $0.8\times 10^4$ in this notation, the significant figures are, 2

The given problem are :

$\frac{1.8\times 10^{-2}}{9\times 10^2}=0.2\times 10^{-4}$

According to the divide and multiplication rules of scientific figures, the final answer is only as precise as the value with the least number of significant figures.

Hence, the answer is, $0.2\times 10^{-4}$

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3 years ago

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