Question

Calculate Srxn for the equation below. (Round to the nearest whole number.)

Answer 1

Answer:The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.

Explanation:

$4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g),\Delta S_{rxn}=?$

$=192.8 J/mol K$

$\Delta S_{O_2}=205.0 J/mol K$

$\Delta S_{H_2O}=188.83 J/mol K$

$\Delta S_{NO}=210.8 J/mol K$

$\Delta S_{rxn}=(4 mol\times \Delta S_{NO}+6 mol\times \Delta S_{H_2O})-(4 mol\times \Delta S_{NH_3}-5 mol\times \Delta S_{O_2})$

$\Delta S_{rxn}=(4\times 210.8 J/mol K+6\times 188.83 J/mol K)-(4\times 192.8 J/mol K+5\times 205.0 J/mol K)$

$\Delta S_{rxn}=179.98 J/K$

The the $\Delta S_{rxn}$ for the given reaction is 179.98 J/K.