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qaws [65]
3 years ago
8

Calculate Srxn for the equation below. (Round to the nearest whole number.)

Chemistry
1 answer:
zaharov [31]3 years ago
4 0

Answer:The the \Delta S_{rxn} for the given reaction is 179.98 J/K.

Explanation:

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g),\Delta S_{rxn}=?

=192.8 J/mol K

\Delta S_{O_2}=205.0 J/mol K

\Delta S_{H_2O}=188.83 J/mol K

\Delta S_{NO}=210.8 J/mol K

\Delta S_{rxn}=(4 mol\times \Delta S_{NO}+6 mol\times \Delta S_{H_2O})-(4 mol\times \Delta S_{NH_3}-5 mol\times \Delta S_{O_2})

\Delta S_{rxn}=(4\times 210.8 J/mol K+6\times 188.83 J/mol K)-(4\times 192.8 J/mol K+5\times 205.0 J/mol K)

\Delta S_{rxn}=179.98 J/K

The the \Delta S_{rxn} for the given reaction is 179.98 J/K.

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How many grams of water are made from the reaction of 16.0 grams of o2? given the reaction: 2h2 o2 --> 2h2o
Jlenok [28]

Answer:

18.0 g H₂O

Explanation:

To find the mass of water (H₂O), you need to (1) convert grams O₂ to moles O₂ (via the molar mass), then (2) convert moles O₂ to moles H₂O (via mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂O to grams H₂O (via the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.

Molar Mass (O₂): 2(15.998 g/mol)

Molar Mass (O₂): 31.996 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

2 H₂ + 1 O₂ -----> 2 H₂O

16.0 g O₂          1 mole            2 moles H₂O         18.014 g
---------------  x  ----------------  x  ---------------------  x  -----------------  = 18.0 g H₂O
                        31.996 g             1 mole O₂             1 mole

6 0
2 years ago
How are cellular respiration and photosynthesis related?
jekas [21]

Answer:

A

Explanation:

Hope it helps

<em> </em><em>#CarryOnLearning</em><em> </em>

3 0
3 years ago
The molar mass of a solid carboxylic acid is determined by titrating a known mass of the acid with a standardized solution of Na
laiz [17]

The answer is: II.The endpoint is recorded when the solution is dark red in color rather than light pink.

The endpoint is the point at which the indicator changes colour in a colourimetric titration and that is point when titration must stop.  

Phenolphthalein is colorless in acidic solutions and pink in basic solutions. If  this indicator change color to dark red, more base is added and endpoint is not accurate.

If the the acid is spilled before titration, that does not make endpoint wrong and molar mass can be calculated.

In this example we can take acetic acid as carboxylic acid; basic salt sodium acetate CH₃COONa is formed from the reaction between weak acid (in this example acetic acid CH₃COOH) and strong base (in this example sodium acetate NaOH).  

Balanced chemical reaction of acetic acid and sodium hydroxide:  

CH₃COOH(aq) + NaOH(aq) → CH₃COONa(aq) + H₂O(l).  

Neutralization is is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH) and a base react quantitatively with each other.

8 0
3 years ago
How many moles are there in 2.30 x 1024 atoms of silver?
Sunny_sXe [5.5K]

Answer:

Step 1 should be convert atoms to moles (n). Step 2 should be convert moles (n) to mass (m).

Step 1

Use dimensional analysis to convert the number of atoms to moles.

1 mole atoms = 6.022 × 10²³ atoms

n(Ag) = 2.3 × 10²⁴ Ag atoms × (1 mol Ag/6.022 × 10²³ Ag atoms) = 3.8193 mol Ag

Step 2

Convert the moles of Ag to mass.

mass (m) = moles (n) × molar mass (M)

n(Ag) = 3.8193 mol Ag

M(Ag) = atomic weight on the periodic table in g/mol = 107.868 g Ag/mol Ag

m(Ag) = 3.8193 mol × 107.868 g/mol = 412 g Ag = 410 g Ag rounded to two significant figures

The mass of 2.3 × 10²⁴ Ag atoms is approximately 410 g.

Explanation:

5 0
3 years ago
Solve the radical equation. what is the extraneous solution to the radical equation? the solution -1 is an extraneous solution.
Arada [10]

Answer:

X = 7

Explanation:

4 0
2 years ago
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